JQuery的：基于列值表行显示/隐藏

问题描述：

我有有是/否为可能值的列的表

I have a table that has a column with Yes/No as possible values

<table id="mytable">
<thead>
<tr>
    <th>
        Col1
    </th>
    <th>
        Col2
    </th>

    <th>
        ActiveYN
    </th>
</tr>
</thead>
<tbody>
<tr>
    <td>
        Apple
    </td>
    <td>
        12345
    </td>

    <td>
        Yes
    </td>
</tr>
<tr>
    <td>
        Orange
    </td>
    <td>
        67890
    </td>

    <td>
        No
    </td>
</tr>
<tr>
    <td>
        Mango
    </td>
    <td>
        456745
    </td>

    <td>
        Yes
    </td>
</tr>

我需要显示的行如果ActiveYN是'是'和隐藏ID ActiveYN是否
我怎样才能访问里面ActiveYN jQuery和显示/隐藏相应的？

I need to show the row if ActiveYN is 'Yes' and Hide id ActiveYN is 'No' How can i access the ActiveYN inside JQuery and show/hide accordingly?

答

演示

$('button').on('click', function () {
    var $rowsNo = $('#mytable tbody tr').filter(function () {
        return $.trim($(this).find('td').eq(2).text()) === "No"
    }).toggle();
});

JQuery的：基于列值表行显示/隐藏

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