Visual Studio 2015如何禁用异常输出

问题描述：

我当时正在制作带有更新和绘图的C#应用程序，但我发现更新确实很慢，尽管没有任何繁琐的表达方式.

I was making a C# application with an update and a draw, and I figured out the update was really slow, although there wasn't any kind of heavy expression.

在独立于Visual Studio启动我的应用程序之后，我发现它的速度快了100倍.问题在于，对于每次try {} catch {}，VStudio都会在输出控制台中输出一条错误消息.每次更新都会显示100条错误消息，这使我的应用程序变慢了.

And after having launched my application independently from Visual Studio, I figured out that it was like 100x faster. The problem was that for every try{} catch {}, VStudio output an error message in the output console. Which made like 100 errors message/ update, which was what slowed down my application.

现在，我用if(){}替换了try {}，它可以正常工作.现在，我想知道是否存在一种方法，使得VStudio不会在控制台中输出错误，以便我可以在不冻结应用程序的情况下做出try {}语句.

Now I replaced the try{} by an if(){}, and it works perfectly. Now I'd like to know wether there's a way that VStudio does not output errors in the console, so that I can make try{} statements without freezing my application.

有什么主意吗?

答

尝试类似

try {
    // code here
}
except YourException {}

如果您不想执行任何操作，请

将 except 块保留为空.如果您想在异常发生时做点什么，请将其放在其中.

Leave except block empty if you don't want to take any action. If you want to do something when exception comes, put that inside there.

Visual Studio 2015如何禁用异常输出

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