在一段时间后获取下个星期天的日期？

问题描述：

I need to return the date of the next Sunday after a certain cut-off point. For example - I'm running a competition website and the cut-off is 10PM on Sunday every week, so if a user were to look at the website after 10PM on a Sunday, it would need to display next weeks date.

At the moment I'm using this:

date('F jS', strtotime('this Sunday', strtotime(date('F jS', time()))));

Which is great, but only works past midnight, so will only display the next Sunday's date at 00:00 on Monday, when I need it at 22:00 on Sunday.

Any help is much appreciated!

我需要在某个截止点之后返回下一个星期日的日期。例如 - 我正在运行一个竞赛网站，截止时间是每周星期日晚上10点，所以如果用户在星期天晚上10点之后查看网站，则需要显示下周的日期。 p >

目前我正在使用它： p>

date（'F jS'，strtotime（'this Sunday'，strtotime（date（' F jS'，time（）））））; code> p>

哪个好，但只能在午夜过后，所以只会在00:00显示下一个星期日的日期周一，我需要在周日的22:00。 p>


非常感谢任何帮助！ p> 
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答

Would something simple like this suffice?

$competitionDeadline = new DateTime('this sunday 10PM');

$date = new DateTime();

if ($date->format('l') === 'Sunday' && $date->format('H') >= '22') {
    // It is past 10 PM on Sunday, 
    // Override next competition dates here... i.e.

    $competitionDeadline = new DateTime('next sunday 10PM');
}

// Wherever you are presenting the competition deadline...
$competitionDeadline->format('Y-m-d H:i:s');

答

As your code returns a timestamp for next sunday @ 00:00:00 just add 22 hours to it, after checking if you are before it is already Sunday and before or after the cutoff time.

// work out if we what this sunday or next sunday
// based on whether we are before or after the cutoff of 22:00
$when = (date('N') == '7' && date('h') > 22) ? 'this' : 'next';

$comp_finish = strtotime("$when Sunday") + (60*60*22);
echo date('d/m/Y H:i:s', $comp_finish);

Giving

14/02/2016 22:00:00

Also you dont need to use the second strtotime as that just generates the equivalent of now which is assumed by the first strtotime anyway

答

You need to check if today is a sunday and if the hour is less than 10pm first:

$next = 'next'; //default to 'next', only change if below matches:
if (date('N') == '7' && date('h') < 22) $next = 'this';

now use that variable in your strtotime:

date('F jS', strtotime("$next Sunday"));

3v4l proof of concept

答

Try this,

echo date('F jS', strtotime('this Sunday', time() + (2*60)));

在一段时间后获取下个星期天的日期？

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