Laravel 5将变量从控制器传递到视图

问题描述：

I'm new to php platforms and what I'm trying to do is to pass a variable from the controller to view for populating a dropdown list with entries from the database, but whatever i'm trying is not working. I get the following error:

Undefined variable: products_create

I can't understand what I'm doing wrong.

Controller

public function create()
{
    $products_create = categories::all(['id', 'category']);

    return View::make('products.create', compact('id', 'category'));
}

View

{!! Form::label('category', 'Categorie') !!}
{!! Form::select('category', $products_create) !!}

我是php平台的新手，我想做的是从控制器传递一个变量用数据库中的条目填充下拉列表的视图，但无论我正在尝试什么都不起作用。我收到以下错误： p>

未定义变量：products_create p> blockquote>

我无法理解我的意思做错了。 p>

控制器 strong> p>

  public function create（）
 {
 $ products_create  = categories :: all（['id'，'category']）; 
 
返回View :: make（'products.create'，compact（'id'，'category'））; 
} 
  代码>  PRE> 
 
  查看强>  p> 
 
 
  {!!  Form :: label（'category'，'Categorie'）!!} 
 {!!  Form :: select（'category'，$ products_create）!!} 
  code>  pre> 
  div>

答

You pass variables to a view in the form of an associative array:

return View::make('products.create', ['products_create' => $products_create]);

compact is a function that helps you build such an array where all keys are the same as the variable name. However you have to pass the actual variable name to the function:

return View::make('products.create', compact('products_create'));

Laravel 5将变量从控制器传递到视图

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