使用RequestDispatcher将数据从servlet传递到另一个servlet

问题描述：

我正在尝试使用RequestDispatcher将数据从一个servlet传递到另一个.这是我的调度程序代码.

I am trying to pass data from one servlet to another using the RequestDispatcher. This is my code for the Dispatcher.

String address;

address = "/Java Resources/src/coreservlets/MapOut.java";

RequestDispatcher dispatcher =
  request.getRequestDispatcher(address);
dispatcher.forward(request, response);

当我尝试运行它时，它给我一个错误，指出该路径不可用.我是否必须包括一些东西，以便调度程序发送到另一个servlet?

When I try to run it, it gives me an error saying the path is unavailable. Do I have to include something for the dispatcher to send to another servlet?

答

您只需要在getRequestDispatcher中传递servlet-mapping的url-pattern.

假设您的servlet映射是web.xml中"MapOut" Servlet的"myMap".那么应该是

Let say your servlet mapping is "myMap" for the "MapOut" Servlet in the web.xml.Then it should be

RequestDispatcher dispatcher = request.getRequestDispatcher("/myMap");
dispatcher.forward(request,response);

转发的Servlet的

doGet()将被调用.

doGet() of forwarded Servlet will be called.

示例:web.xml

Example: web.xml

      <servlet>
        <description></description>
        <servlet-name>MapOut</servlet-name>
        <servlet-class>coreservlets.MapOut</servlet-class>
      </servlet>
      <servlet-mapping>
        <servlet-name>MapOut</servlet-name>
        <url-pattern>/myMap</url-pattern> <!-- You can change this-->
      </servlet-mapping>

使用RequestDispatcher将数据从servlet传递到另一个servlet

相关推荐