请问动态创建控件如何等分排列
请教动态创建控件怎么等分排列
------解决思路----------------------
这是我项目中用到的，可以参考。
本帖最后由 wangjimmy1994 于 2015-03-11 15:47:27 编辑
本人新手，想请教下，比如我动态创建50个按钮，怎么动态设置让它们5个一行排列在屏幕上，属性是怎么动态设置的------解决思路----------------------
@SuppressLint("NewApi")
public class ButtonLayout extends LinearLayout {
private int cellWidth;
private int cellHeight;
public ButtonLayout(Context context) {
super(context);
}
public ButtonLayout(Context context, AttributeSet attrs) {
super(context, attrs);
}
public ButtonLayout(Context context, AttributeSet attrs, int defStyle) {
super(context, attrs, defStyle);
}
public void setmCellWidth(int w) {
cellWidth = w;
requestLayout();
}
public void setmCellHeight(int h) {
cellHeight = h;
requestLayout();
}
/**
* 控制子控件的换行
*/
@Override
protected void onLayout(boolean changed, int l, int t, int r, int b) {
int width = cellWidth;
int height = cellHeight;
int columns = (r - l) / width;//TODO
if (columns < 0) {
columns = 1;
}
int x = 0;
int y = 0;
int i = 0;
int count = getChildCount();
for (int j = 0; j < count; j++) {
final View childView = getChildAt(j);
// 获取子控件Child的宽高
int w = childView.getMeasuredWidth();
int h = childView.getMeasuredHeight();
// 计算子控件的顶点坐标
int left = x + (width - w) / 2;
int top = y + (height - h);
childView.layout(left, top, left + w, top + h);
if (i >= (columns - 1)) {
i = 0;
x = 0;
y += height;
} else {
i++;
x += width;
}
}
}
/**
* 计算控件及子控件所占区域
*/
@Override
protected void onMeasure(int widthMeasureSpec, int heightMeasureSpec) {
// 创建测量参数
int cellWidthSpec = MeasureSpec.makeMeasureSpec(cellWidth,
MeasureSpec.AT_MOST);
int cellHeightSpec = MeasureSpec.makeMeasureSpec(cellHeight,
MeasureSpec.AT_MOST);
int count = getChildCount();
for (int i = 0; i < count; i++) {
View childView = getChildAt(i);
childView.measure(cellWidthSpec, cellHeightSpec);
}
setMeasuredDimension(resolveSize(cellWidth * count, widthMeasureSpec),
resolveSize(cellHeight * count, heightMeasureSpec));
}
}
这是我项目中用到的，可以参考。