求指导，编程

求指导，求一个编程。
题目：输入年月日，输出该天是该年第几天.
最好用初学者会的语言编写，先感谢各位啦，谢谢！

------解决方案--------------------
用不着这么长的switch，利用数组就能大幅度简化它。

C/C++ code

#include<stdio.h>
main()
{
    int year,month,days;
    int i,d,s;
    int monthdays[]={31,28,31,30,31,30,31,31,30,31,30,31};
    printf("Please input the numbers year,month,day:\n");
    scanf("%d%d%d",&year,&month,&days);
    s=0;
    for(i=1;i<month;i++)
    {
        s+=monthdays[i-1];
        if(i==2&&((year%4==0)&&(year%100!=0)||(year%400==0)))   //  这里的条件是百年不润
            s++;
    }
    printf("%d年%d月%d日是这年的%d天\n",year,month,days,s+days);
}

------解决方案--------------------

探讨

用不着这么长的switch，利用数组就能大幅度简化它。
C/C++ code
#include<stdio.h>
main()
{
int year,month,days;
int i,d,s;
int monthdays[]={31,28,31,30,31,30,31,31,30,31,30,31};
printf("Please input the num……

------解决方案--------------------

C/C++ code


#include <stdlib.h>    
#include <stdio.h>
static char daytab[2][13] = {
    {0, 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31},
    {0, 31, 29, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31}
};
/* day_of_year: set day of year from month & day */
int day_of_year(int year, int month, int day)
{
    int i, leap;
    leap = year%4 == 0 && year%100 != 0 || year%400 == 0;
    for (i = 1; i < month; i++)
        day += daytab[leap][i];
    return day;
}

/* month_day: set month, day from day of year */
void month_day(int year, int yearday, int *pmonth, int *pday)
{
    int i, leap;
    leap = year%4 == 0 && year%100 != 0 || year%400 == 0;
    for (i = 1; yearday > daytab[leap][i]; i++)
        yearday -= daytab[leap][i];
    *pmonth = i;
    *pday = yearday;
}
int main()
{
    int m, d;
    month_day(1988, 60, &m, &d);
    printf("%d month %d date\n", m, d);
    system("pause");
}

------解决方案--------------------
#include<stdio.h>

int main()
{
	int y, m, d;
	int a[13] = {0,31,0,31,30,31,30,31,31,30,31,30,31};

	while( scanf("%d%d%d",&y,&m,&d)==3 )
	{
		int i, num;

		a[2] = y % ( y % 100 ? 4 : 400 ) ? 28 : 29;
		if ( d<1 || d>a[m] || m<1 || m>12 )
		{
			printf("输入错误!\n请重新输入日期:\n\n");
		}
		else  
		{
			for( i=1, num=0; i<m; i++ )
			{
				num += a[i];
			}
			num += d;  //这一年的第几天
			printf("%d\n",num);
		}
	}

	return 0;
}[code=C/C++][/code]

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