自个儿写一个函数，实现字符串的拷贝 用纯C写

myMemCopy(char *dest, char *source, int size)
{
  int longNum = 0;
  int shortNum = 0;
  int charNum = 0;

   longNum = size / 4;
   shor5Num = (size % 4) / 2;
   charNum = size % 2;

   // 4字节Copy
   for(int iCnt = 0; iCnt < longNum; iCnt++)
   {
     *(long *)dest = *(long *)source;

     source = source + 4;
     dest = dest + 4;
   }
 
   // 剩余2字节copy
   for(int iCnt = 0; iCnt < shortNum; iCnt++)
   {
     *(short *)dest = *(short *)source;

     source = source + 2;
     dest = dest + 2;
   }

   // 剩余1字节Copy
   for(int iCnt = 0; iCnt < charNum; iCnt++)
   {
     *(short *)dest = *(short *)source;

     source = source + 1;
     dest = dest + 1;
   }
}

------解决方案--------------------
最简单的。
char *copy(char *to,const char *from)
{
while (*to++=*from++);
return to;
}

------解决方案--------------------
呵呵，这多像网上出的面试题啊！

------解决方案--------------------

C/C++ code

1.得分最低的
void * strcpy(char *dest, const char *src)
{
   while(*dest++ = *src++);
}
2.好一点的
char * strcpy(char *dest,const char *src)
{
    char * temp;
    temp = dest;
    while(*dest++ = *src++);
    return temp;
}
3可以接受的
char * strcpy(char *dest,const char *src)
{
     assert( dest != src);
     assert( dest != NULL || src != NULL);
     char *temp = dest;
     while(*dest++ = *src++);
     return temp;
}

------解决方案--------------------

探讨

写一个，没测试。。
C/C++ code

myMemCopy(char *dest, char *source, int size)
{
int longNum = 0;
int shortNum = 0;
int charNum = 0;

longNum = size / 4;
shor5Num = (size % 4) / 2;
charNum = siz……

------解决方案--------------------

探讨

呵呵，这多像网上出的面试题啊！

------解决方案--------------------
都觉得面熟。
------解决方案--------------------
见过了，面试题
------解决方案--------------------

C/C++ code

char * strcpy(char *dest,const char *src)
{
    char * temp;
    temp = dest;
    while(*dest++ = *src++)
        ;
    return temp;
}