hdoj1012--u Calculate e
Problem Description
A simple mathematical formula for e is
where n is allowed to go to infinity. This can actually yield very accurate approximations of e using relatively small values of n.
where n is allowed to go to infinity. This can actually yield very accurate approximations of e using relatively small values of n.
Output
Output the approximations of e generated by the above
formula for the values of n from 0 to 9. The beginning of your output should
appear similar to that shown below.
Sample Output
n e
- -----------
0 1
1 2
2 2.5
3 2.666666667
4 2.708333333
#include<iostream> #include <iomanip> using namespace std; int main() { int i,n; double s,t; cout<<"n e"<<endl; cout<<"- -----------"<<endl; cout<<"0 1"<<endl; cout<<"1 2"<<endl; cout<<"2 2.5"<<endl; s=2.5; n=2; for(i=3; i<=9; i++) { n=i*n; s+=1.0/n; cout<<i<<" "<<fixed<<setprecision(9)<<s<<endl; } return 0; }