如何检查鼠标是否在jQuery中的元素上?
有一个快速的&在jQuery中缺少的简单方法吗?
Is there a quick & easy way to do this in jQuery that I'm missing?
我不想使用mouseover事件，因为我已经将它用于其他用途.我只需要知道鼠标在给定的时刻是否位于某个元素上即可.
I don't want to use the mouseover event because I'm already using it for something else. I just need to know if the mouse is over an element at a given moment.
如果只有一个"IsMouseOver"功能，我想做这样的事情:
I'd like to do something like this, if only there was an "IsMouseOver" function:
function hideTip(oi) {
setTimeout(function() { if (!IsMouseOver(oi)) $(oi).fadeOut(); }, 100);
}
在鼠标超时上设置超时以淡出，并将返回值存储到对象中的数据.然后onmouseover，如果数据中有值，则取消超时.
Set a timeout on the mouseout to fadeout and store the return value to data in the object. Then onmouseover, cancel the timeout if there is a value in the data.
在淡出回调中删除数据.
Remove the data on callback of the fadeout.
使用mouseenter/mouseleave实际上更便宜，因为当孩子将鼠标悬停/鼠标移开时，它们不会触发菜单.
It is actually less expensive to use mouseenter/mouseleave because they do not fire for the menu when children mouseover/mouseout fire.