根据Pandas数据框中的特定值过滤所有行

问题描述：

当条件满足时，我有一个数据帧为是，否则为否。现在，我想检索其中有否的所有行。

I have a dataframe that has "yes" when a condition is satisfied and "no" when it is not. Now, I would like to retrieve all the rows that has "No" in it.

我尝试使用这段代码：

 df2 = df[df['Logs'].astype(str).str.contains('No')] 
 df3 = df[df['Jobs'].astype(str).str.contains('No')] 
 df4 = df[df['Performance'].astype(str).str.contains('No')] 
 df5 = df2 | df3 | df4

我收到错误不支持的操作数类型。

I got the error "unsupported operand types".

例如：

 MachineName    Logs   Jobs   Performance
 121            Yes    No      Yes
 122            Yes    Yes     Yes
 123            Yes    No      No
 125            Yes    Yes     Yes
 126            No     No      No

输出：

 MachineName    Logs   Jobs   Performance
 121            Yes    No      Yes
 123            Yes    No      No
 126            No     No      No

答

所有列的平等检查'否'，然后使用 any 以获取一个布尔数组。

Do an equality check on all columns you want to be 'No', and then use any to get a Boolean array.

condition = (df[['Logs', 'Jobs', 'Performance']] == 'No').any(axis=1)
df2 = df[condition]

结果输出如预期：

   MachineName Logs Jobs Performance
0          121  Yes   No         Yes
2          123  Yes   No          No
4          126   No   No          No

根据Pandas数据框中的特定值过滤所有行

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