Django模板中的字典表

问题描述：

我有一个字典：

field = 

{
   u'Birthday:': [datetime.date(2012, 4, 6), datetime.date(2012, 4, 27)],
   u'Education': [u'A1', u'A2'],
   u'Job:': [u'job1', u'job2'],
   u'Child Sex:': [u'M', u'F']
}

我的模板代码是：

<table width="100%" border="0">
     <tr>
        {% for k, v in field.items %}
            <th>{{ k }}</th>
        {% endfor %}
     </tr>
     <tr>
       {% for k,v in field.items %}
            <td>
                <table width="100%" border="0">
                 {% for a in v %}
                     <tr class="{% cycle 'odd' 'even' %}"><td>{{ a }}</td></tr>
                 {% endfor %}
                </table>
            </td>
        {% endfor %}
     </tr>
</table>

我想将字典键显示为表头，并将esach值显示为行：

I want to show dictionary keys as table headers and esach value as row:

Birthday                          Education      Job        Child Sex
datetime.date(2012, 4, 6)         A1             job1       M
datetime.date(2012, 4, 27)        A2             job2       F

但是我必须插入第二个表。有没有办法把字典键作为表头，并将esach值作为行？

But I have to insert a second table. Is there any way toshow dictionary keys as table headers and esach value as rows?

提前感谢

答

如果您将数据作为表中的字典提供，您可以使模板代码更容易阅读。它会更像这样：

You can make the template code a lot easier to read if you provide the data as a table in your dictionary. It would look more like this:

field = {
    'headers': [u'Birthday:', u'Education', u'Job', u'Child Sex'],
    'rows': [[datetime.date(2012, 4, 6), u'A1', u'job1', u'M']
            ,[datetime.date(2012, 4, 27), u'A2', u'job2', u'F']]
}

您现在可以按如下方式遍历标题：

You can now iterate over the headers as follows:

<tr>
{% for header in field.headers %}
    <th>{{ header }}</th>
{% endfor %}
</tr>

每行可以使用以下方式显示：

And each row can be displayed using:

<tr>    
{% for value in field.rows %}
    <td>{{ value }}</td>
{% endfor %}
</tr>

现在，您可以获取'头文件值使用 field.keys（）：

Now, you can obtain the 'headers' value using field.keys():

[u'Birthday:', u'Education', u'Job:', u'Child Sex:']

您可以使用以下循环获取'值'（其中 2 是行数）：

You can get the 'values' using the following loop (where 2 is the number of rows):

rows = []
for i in xrange(2):
    row = []
    for k in field.keys():
        row.append(field[k][i])
    rows.append(row)

或作为单行：

rows = [[field[k][i] for k in field.keys()] for i in xrange(2)]

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