用一个空格替换所有非字母数字字符、换行符和多个空格
问题描述：
我正在寻找一个简洁的 RegEx 解决方案来替换
I'm looking for a neat RegEx solution to replace
- 所有非字母数字字符
- 所有换行符
- 空格的所有多个实例
一个空格
对于那些在家玩耍的人(以下确实有效)
For those playing at home (the following does work)
text.replace(/[^a-z0-9]/gmi, " ").replace(/\s+/g, " ");
我的想法是 RegEx 可能足以在一个语句中实现这一点.我认为需要的组件是
My thinking is RegEx is probably powerful enough to achieve this in one statement. The components i think id need are
-
[^a-z0-9]- 删除非字母数字字符 -
\s+- 匹配任何空格集合 -
\r?\n|\r- 匹配所有新行 -
/gmi- 全局、多行、不区分大小写
-
[^a-z0-9]- to Remove non Alpha-Numeric characters -
\s+- match any collections of spaces -
\r?\n|\r- match all new line -
/gmi- global, multi-line, case insensitive
但是，我似乎无法以正确的方式设置正则表达式的样式(以下不起作用)
However, i cant seem to style the regex in the right way (the following doesn't work)
text.replace(/[^a-z0-9]|\s+|\r?\n|\r/gmi, " ");
输入
234&^%,Me,2 2013 1080p x264 5 1 BluRay
S01(*&asd 05
S1E5
1x05
1x5
期望输出
234 Me 2 2013 1080p x264 5 1 BluRay S01 asd 05 S1E5 1x05 1x5
答
注意，\W 保留下划线.[^a-zA-Z0-9] 的简短等价物是 [\W_]
Be aware, that \W leaves the underscore. A short equivalent for [^a-zA-Z0-9] would be [\W_]
text.replace(/[\W_]+/g," ");
\W 是 shorthand \w 用于 [A-Za-z0-9_] 单词字符(包括下划线)
\W is the negation of shorthand \w for [A-Za-z0-9_] word characters (including the underscore)