PHP在数组中搜索值 - 如果全部是数字则返回true，否则返回false

问题描述：

Ok, Stupid question here... just trying to do a search in an array to be sure all of the values are numeric, if not, I need to return false. What's the quickest way to do this. This array could be HUGE. By the way, it's not a multi-dimensional array, and doesn't have any sub-arrays within it. It's just a one level array... example:

array(1, 5, 6, 2, 44, 92, 50, string);

This should return false, cause string is one of the values in the array and is not a number. I mean, is there a faster way to do this than using foreach on the array and using intval on every value??

Thanks guys :)

好的，这里有愚蠢的问题......只是想在数组中进行搜索以确保所有的值是数字，如果没有，我需要返回false。什么是最快的方法。这个数组可能很大。顺便说一句，它不是一个多维数组，并且其中没有任何子数组。它只是一个单级数组...例如： p>

  array（1,5,6,2,44,92,50，string）; 
  code>   pre> 
 
 这应该返回false，因为string是数组中的值之一而不是数字。 我的意思是，有没有比在数组上使用 foreach  code>并在每个值上使用 intval  code>更快的方法？ p> 
 
 
 谢谢你们：） p> 
  div>

答

You can use is_numeric function -

$count = count($your_array);

for($index=0; $index<$count; $index++)
{
    if( !is_numeric($your_array[index]) )
        return false;
}

答

foreach($array as $value)
{
    if(!is_numeric($value))
    {
       return false;
    }
}

答

  if(in_array(false, array_map("is_numeric", array(1, 2, 3, 4, 5, "string"))))
    return false;

I have not researched the performance, sorry. But these are inbuilt functions which are allegedly faster than anything custom one can write...

PHP在数组中搜索值 - 如果全部是数字则返回true，否则返回false

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