我应该在Laravel 5的会话变量中存储哪些数据

问题描述：

我是laravel的新手.我一直在与不同类型的用户一起开发laravel 5应用程序.我需要有关视图的不同部分中当前登录的用户类型的信息:

I am new to laravel. I have been working on a laravel 5 app with different types of users. I need information about which type of user is currently logged in different sections of my views:

目前，我已经在下面的各种控制器方法上进行了类似的操作，并且使用了user对象，我可以确定它在我看来是哪种类型的用户:

Currently, I have been doing something like below on various controller methods and with the user object, I can determine which type of user it is in my view:

在控制器中:

public function someMethod(){
    $user = Auth::user();
    return view('applications.show', compact('user'));
}

在视图中:

if($user->is_manager)
   // do this
else if($user->is_admin)
  // do that

因为我需要各种视图中有关用户类型的信息，所以我已经在多个地方调用了Auth::user()，并且我开始认为这会增加数据库的负担.将用户类型存储在会话变量中更好吗?我应该在会话中存储哪种数据?

Because I need information about the user-type in various views, I have been calling Auth::user() in several places and I am beginning to think that this is adding some load on the DB. Is it better to store the user-type in a session variable and what kind of data should I be storing in my session?

答

将其存储在会话中不是问题.

It wouldn't be an issue storing it in the session.

在User类的is_manager函数中，您可以执行以下操作...

In the is_manager function in your User class, you could do something like the following...

public function is_manager()
{
    // Check if the session has been set first.
    if(\Session::has('is_manager')) {
        return \Session::get('is_manager');
    }

    // Do your necessary logic to determine if the user is a manager, ex...
    $is_manager = $this->roles()->where('name', '=', 'manager')->count() == 1;

    // Drop it in the session
    \Session::put('is_manager', $is_manager);

    return $is_manager;
}

请记住，如果您将会话驱动程序设置为数据库，那么这显然无济于事.

Keep in mind if your session driver is set to database, then this obviously isn't going to help.

我应该在Laravel 5的会话变量中存储哪些数据

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