确定为什么不能腌制对象

问题描述：

我正在从类型为Object的api接收对象t.我无法腌制它，得到了错误:

I'm receiving an object, t, from an api of type Object. I am unable to pickle it, getting the error:

  File "p.py", line 55, in <module>
    pickle.dump(t, open('data.pkl', 'wb'))
  File "/usr/lib/python2.6/pickle.py", line 1362, in dump
    Pickler(file, protocol).dump(obj)
  File "/usr/lib/python2.6/pickle.py", line 224, in dump
    self.save(obj)
  File "/usr/lib/python2.6/pickle.py", line 313, in save
    (t.__name__, obj))
pickle.PicklingError: Can't pickle 'Object' object: <Object object at 0xb77b11a0>

当我执行以下操作时:

for i in dir(t): print(type(i))

我只得到字符串对象:

<type 'str'>
<type 'str'>
<type 'str'>
...
<type 'str'>
<type 'str'>
<type 'str'>

如何打印我的Object对象的内容，以了解为什么不能腌制它?

How can I print the contents of my Object object in order to understand why it cant be pickled?

该对象还可能包含指向QT对象的C指针，在这种情况下，我对该对象进行腌制是没有意义的.但是我还是想看看该对象的内部结构以建立它.

Its also possible that the object contains C pointers to QT objects, in which case it wouldn't make sense for me to pickle the object. But again I would like to see the internal structure of the object in order to establish this.

答

您可能需要阅读 Python文档，然后检查API的Object类.

You may want to read the python docs and check your API's Object class afterwards.

关于对象的内部结构"，通常实例属性存储在__dict__属性中(并且由于未腌制类属性，因此您仅关心实例属性)-但请注意，您还将必须递归检查每个属性的__dict__.

With respect to the "internal structure of the object", usually instance attributes are stored in the __dict__ attribute (and since class attributes are not pickled you only care about the instance attributes) - but note that you'll also have to recursively inspect the __dict__s for each attribute.

确定为什么不能腌制对象

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