Postgres:将单行转换为多行(不可透视)
问题描述:
我有一张桌子:
Table_Name: price_list
---------------------------------------------------
| id | price_type_a | price_type_b | price_type_c |
---------------------------------------------------
| 1 | 1234 | 5678 | 9012 |
| 2 | 3456 | 7890 | 1234 |
| 3 | 5678 | 9012 | 3456 |
---------------------------------------------------
我需要在Postgres中进行选择查询,其结果如下:
I need a select query in Postgres which gives result like this:
---------------------------
| id | price_type | price |
---------------------------
| 1 | type_a | 1234 |
| 1 | type_b | 5678 |
| 1 | type_c | 9012 |
| 2 | type_a | 3456 |
| 2 | type_b | 7890 |
| 2 | type_c | 1234 |
...
任何对指向相似示例的链接的帮助都非常感谢。
Any help with links to similar examples greatly appreciated.
答
带有 LATERAL $ c的单个
SELECT
$ c>加入 VALUES
表达式即可完成工作:
A single SELECT
with a LATERAL
join to a VALUES
expression does the job:
SELECT p.id, v.*
FROM price_list p
, LATERAL (
VALUES
('type_a', p.price_type_a)
, ('type_b', p.price_type_b)
, ('type_c', p.price_type_c)
) v (price_type, price);
相关:
- Convert one row into multiple rows with fewer columns
- SELECT DISTINCT on multiple columns