找到＆QUOT;字符串长度QUOT;一个int
问题描述：
基本上我想要返回的位数在INT - >值是这样的：
basically I want to return the number of digits in the int -> values like this:
(int)1 => 1
(int)123 => 3
(int)12345678 => 8
我一无所知C，所以请多多包涵。我知道目标C，但我用整型和浮点型，而不是NSNumbers。我知道我可以在整数转换成目标C对象，但这似乎faffy，如果我可以用C做，我就知道它的未来。
I know nothing about C, so please bear with me. I know objective c, but I use ints and floats instead of NSNumbers. I realise I could convert the ints into objective c objects, but this seems faffy, and if I can do it with C I'll know it for the future.
感谢
答
使用
int d = (value == 0 ? 1 : (int)(log10(value)+1));
请注意，对于负数，这并不工作，你将不得不使用
Note that this doesnt work for negative numbers, you'll have to use
int d = (value == 0 ? 1 : ((int)(log10(fabs(value))+1) + (value < 0 ? 1 : 0)));
这为负号加1，如果值是负的。