将Int [int8]的带符号数组快速转换为Int [UInt8]的无符号数组
问题描述：
如何将[Int8]的有符号数组转换为[UInt8]的无符号数组。
How to convert signed array of [Int8] to unsigned array of [UInt8].
let arryData: [Int8] = [-108, 11, -107, -14, 35, -57, -116, 118, 54, 91, 12, 67, 21, 29, -44, 111]
我只想将上面的内容转换为无符号[UInt8]数组。如何在迅捷中实现这一目标。在此先感谢。
I just want to convert this above into array of Unsigned [UInt8]. How to achieve this in swift.? Thanks in advance.
答
如果您打算将带符号的8位整数转换为
无符号的具有相同的位表示（例如 -1 - > 255 ）：
If your intention is to convert signed 8-bit integers to
unsigned ones with the same bit representation (e.g. -1 -> 255):
let intArray: [Int8] = [0, 1, 2, 127, -1, -2, -128]
let uintArray = intArray.map { UInt8(bitPattern: $0) }
print(uintArray)
// [0, 1, 2, 127, 255, 254, 128]