在PHP中将字符串转换为日期

问题描述：

如何将字符串05/Feb/2010:14:00:01转换为unixtime?

How can I convert this string 05/Feb/2010:14:00:01 to unixtime ?

答

对于PHP 5.3，这应该可以工作.您可能需要通过传递$ dateInfo ['is_dst']来摆弄，无论如何对我来说都是无效的.

For PHP 5.3 this should work. You may need to fiddle with passing $dateInfo['is_dst'], wasn't working for me anyhow.

$date = '05/Feb/2010:14:00:01';
$dateInfo = date_parse_from_format('d/M/Y:H:i:s', $date);
$unixTimestamp = mktime(
    $dateInfo['hour'], $dateInfo['minute'], $dateInfo['second'],
    $dateInfo['month'], $dateInfo['day'], $dateInfo['year'],
    $dateInfo['is_dst']
);

之前的版本应该可以使用.

Versions prior, this should work.

$date = '05/Feb/2010:14:00:01';
$format = '@^(?P<day>\d{2})/(?P<month>[A-Z][a-z]{2})/(?P<year>\d{4}):(?P<hour>\d{2}):(?P<minute>\d{2}):(?P<second>\d{2})$@';
preg_match($format, $date, $dateInfo);
$unixTimestamp = mktime(
    $dateInfo['hour'], $dateInfo['minute'], $dateInfo['second'],
    date('n', strtotime($dateInfo['month'])), $dateInfo['day'], $dateInfo['year'],
    date('I')
);

您可能不喜欢正则表达式.您当然可以对其进行注释，但并不是每个人都喜欢.因此，这是另一种选择.

You may not like regular expressions. You could annotate it, of course, but not everyone likes that either. So, this is an alternative.

$day = $date[0].$date[1];
$month = date('n', strtotime($date[3].$date[4].$date[5]));
$year = $date[7].$date[8].$date[9].$date[10];
$hour = $date[12].$date[13];
$minute = $date[15].$date[16];
$second = $date[18].$date[19];

或替换或爆炸，无论您希望解析哪个字符串.

Or substr, or explode, whatever you wish to parse that string.

在PHP中将字符串转换为日期

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