将字符串十进制转换为int

问题描述：

我有一个字符串"246246.246"，我想传递给IConvertable接口ToInt16，ToInt32，ToIn64.将带小数位的字符串解析为整数的最佳方法是什么?

I have a string "246246.246" that I'd like to pass to the IConvertable interface, ToInt16, ToInt32, ToIn64. What is the best way to parse a string with decimal places to an integer?

这是一个解决方案，但是有更好的解决方案吗?

This is a solution, but is there a better solution?

string value = "34690.42724";
Convert.ToInt64(Convert.ToDouble(value));

答

要进行此舍入舍入，可以执行以下操作:

To do this discounting rounding you could do:

Convert.ToInt64(Math.Floor(Convert.ToDouble(value)));

如果需要四舍五入，可以将Math.Floor替换为Math.Round.

If you need to round you could replace Math.Floor with Math.Round.

编辑:由于您在评论中提到要四舍五入:

Since you mentioned in a comment that you'll be rounding:

Convert.ToInt64(Math.Round(Convert.ToDouble(value)));

如果您不得不担心本地化/全球化的问题，那么正如@xls所说，您应该在转换中应用CultureInfo.

If you have to worry about localization/globalization then as @xls said you should apply a CultureInfo in the conversions.

使用字符串函数的替代方法(不是很优雅的IMO-也许可以通过谓词函数来实现优雅的装饰):

Edit 2: Alternative method using a string function (not terribly elegant IMO - maybe it could be elegantized with a predicate function):

Convert.ToInt64(value.Substring(0, value.IndexOf('.') > 0 ? value.IndexOf('.') : value.Length));

将字符串十进制转换为int

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