如何在C中将int数组转换为字节数组
嘿，我想知道如何将C中的Int数组转换为字节数组，以及声明方法是什么.如果它更简单并且不使用指针，我将不胜感激.谢谢你的评论
hey i would like to know how you could cast an Int array in C to an byte array and what would be the declaration method. I would appreciate if it is simpler and no use of pointers. thanks for the comments
ex:将int addr [500]转换为byte []
ex: int addr[500] to byte[]
另外，我还希望结尾字节数组具有相同的数组名称.
Plus I would also want the ending byte array to have the same array name.
如果，您试图将int数组后面的内存作为字节数组进行重新解释，并且只有这样:
If you are trying to reinterpret the memory behind the int array as an array of bytes, and only then:
int ints[500];
char *bytes = (char *) ints;
您不能执行此操作而不求助于指针强制转换，因为声明[]数组意味着在堆栈上进行分配，并且不能用于重新解释现有内存.
You cannot do this without resorting to pointer casting, as declaring a [] array implies allocation on stack, and cannot be used for reinterpretation of existing memory.
很显然，您需要知道自己在做什么.对于每个int，通常会有4个char(通常取决于平台等)，因此您的新数组将具有500*4个元素.查看以下内容的输出:
Obviously, you need to know what you are doing. For each int there will be (typically, depending on platform etc.) 4 chars, so your new array would have 500*4 elements. Check out what the output of:
printf("char size: %d, int size: %d", sizeof(char), sizeof(int));
告诉您要确定.
如果，您尝试将每个int解释为char，即要获得与int相同的char个数，则您不能不进行循环和手动转换(通常到新的内存位置)就无法做到这一点.
If you are trying to interpret each int as a char, i.e. to get the same number of chars, as there were ints, then you cannot do this without a loop and manual conversion (to a new memory locaton, normally).