使用C ++样式转换将int转换为char

问题描述：

在传统C语言中，您可以执行以下操作：

In traditional C you can do:

int i = 48;
char c = (char)i;
//Now c holds the value of 48. 
//(Of course if i > 255 then c will not hold the same value as i).

哪种c ++转换方法（static_cast，reinterpret_cast）适合完成此工作？ p>

Which of the c++ casting methods (static_cast, reinterpret_cast) is suited for getting this job done?

答

即使在数字类型失去精度的情况下，您也可以在数字类型之间进行隐式转换：

You can implicitly convert between numerical types, even when that loses precision:

char c = i;

但是，您可能希望启用编译器警告，以避免潜在的有损转换。如果这样做，则使用 static_cast 进行转换。

However, you might like to enable compiler warnings to avoid potentially lossy conversions like this. If you do, then use static_cast for the conversion.

其他类型的转换：

dynamic_cast 仅适用于多态类类型的指针或引用；

const_cast 不能更改类型，只能更改 const 或 volatile 限定词；

reinterpret_cast 用于特殊情况，在指针或引用与完全不相关的类型之间进行转换。具体来说，它不会进行数字转换。

C风格和函数风格的强制转换可以执行 static_cast ， const_cast 和 reinterpret_cast 才能完成工作。

dynamic_cast only works for pointers or references to polymorphic class types;
const_cast can't change types, only const or volatile qualifiers;
reinterpret_cast is for special circumstances, converting between pointers or references and completely unrelated types. Specifically, it won't do numeric conversions.
C-style and function-style casts do whatever combination of static_cast, const_cast and reinterpret_cast is needed to get the job done.

使用C ++样式转换将int转换为char

相关推荐