如何在Android的下载目录中获取每个文件的完整路径和名称
我将要开发一个应用程序,用户可以在其中从下载目录中选择文件.现在,我需要用户选择的文件的路径+名称.
I am going to develop an app, where user can choose File from a Download directory. Now i need the path + name of the file, which the user has chosen.
DownloadManager dm = (DownlaodManager) getSystemService(DOWNLOAD_SERVICE);
通过这种方式,用户可以选择文件.现在,我需要选择文件的绝对路径.但是这里的问题是,如果用户选择一个文件,该文件将处于打开状态(这不应该发生)
By this way the user can choose the file. Now i need the absoloute path of the file, which is choosen. But the problem here is, if the user chosse a file, the file will be open(this shouldn't be happen)
你们中的任何人都可以帮我吗?
Can anyone of you help me with that?
使用, Environment.getExternalStoragePublicDirectory(Environment.DIRECTORY_DOWNLOADS);
访问文件夹,然后 File.listFiles()
访问该目录中的单个文件.
Use,
Environment.getExternalStoragePublicDirectory(Environment.DIRECTORY_DOWNLOADS);
to access the folder, and File.listFiles()
to access individual files from that directory.
看这个简单的例子,
编写一种方法来浏览和列出 Downloads
目录中的每个文件,如果在 Downloads
文件夹中找到目录,请同时列出其文件
write a method to browse and list each file from Downloads
directory,
and if a directory is found in Downloads
folder, list its files too,
public void getFilesFromDir(File filesFromSD) {
File listAllFiles[] = filesFromSD.listFiles();
if (listAllFiles != null && listAllFiles.length > 0) {
for (File currentFile : listAllFiles) {
if (currentFile.isDirectory()) {
getFilesFromDir(currentFile);
} else {
if (currentFile.getName().endsWith("")) {
// File absolute path
Log.e("File path", currentFile.getAbsolutePath());
// File Name
Log.e("File path", currentFile.getName());
}
}
}
}
}
获取您的 Downloads
目录的路径,并将其作为参数传递给上述方法,
Get the path of your Downloads
directory and pass it as parameter in your above method,
File downloadDir = new File(Environment.getExternalStoragePublicDirectory(
Environment.DIRECTORY_DOWNLOADS).getAbsolutePath());
getFilesFromDir(downloadDir);