cUrl 到 apache HttpClient

问题描述：

我通常使用 cUrl 一分钟到达我的终点.但我还没有到需要考虑构建客户端的阶段.

I normally use cUrl to hit my endpoint at the minute. But am not at the stage where I need to think about building the client.

我通常通过以下方式到达我的端点:

I normally hit my endpoint the following way :

curl -u "adminaccount:adminpassword" http://localhost:8080/api/private/v1/endpoint/

假设我有以下代码

 HttpGet getRequest = new HttpGet(
        "http://localhost:8080/api/private/v1/endpoint/");

 HttpResponse response = httpClient.execute(getRequest);

现在，我显然需要传入等效的内容:

Now, I obviously need to pass in the equivalent of that :

-u" adminaccount:adminpassword"

不知何故.有什么想法吗?

somehow. Any ideas?

答

创建 HttpClient 时:

When creating your HttpClient:

CredentialsProvider credsProvider = new BasicCredentialsProvider();
        credsProvider.setCredentials(
                new AuthScope("localhost", 8080),
                new UsernamePasswordCredentials("adminaccount", "adminpassword"));
        CloseableHttpClient httpclient = HttpClients.custom()
                .setDefaultCredentialsProvider(credsProvider)
                .build();

但是是的，不要因为被告知用谷歌搜索而生气，而是去谷歌搜索.例如，从谷歌搜索HttpClient 身份验证示例"开始.网站的规则很明确——先做功课"

But yeah instead of getting in a huff about being told to google it, just go google it. Start with googling for "HttpClient authentication example" for example. The rules of the site are quite clear - "Do your homework first"

cUrl 到 apache HttpClient

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