如何在Android中解析JSON?

Android具有解析内置json所需的所有工具.示例如下，不需要GSON或类似的东西.

Android has all the tools you need to parse json built-in. Example follows, no need for GSON or anything like that.

获取您的JSON:

假设您有一个json字符串

Assume you have a json string

String result = "{\"someKey\":\"someValue\"}";

创建 JSONObject :

Create a JSONObject:

JSONObject jObject = new JSONObject(result);

如果您的json字符串是一个数组，例如:

If your json string is an array, e.g.:

String result = "[{\"someKey\":\"someValue\"}]"

然后您应该使用下面显示的JSONArray而不是JSONObject

then you should use JSONArray as demonstrated below and not JSONObject

获取特定字符串

String aJsonString = jObject.getString("STRINGNAME");

获取特定的布尔值

boolean aJsonBoolean = jObject.getBoolean("BOOLEANNAME");

获取特定整数

int aJsonInteger = jObject.getInt("INTEGERNAME");

获取特定的时间

long aJsonLong = jObject.getLong("LONGNAME");

要获得特定的双打

double aJsonDouble = jObject.getDouble("DOUBLENAME");

要获取特定的 JSONArray :

To get a specific JSONArray:

JSONArray jArray = jObject.getJSONArray("ARRAYNAME");

要从数组中获取项目

for (int i=0; i < jArray.length(); i++)
{
    try {
        JSONObject oneObject = jArray.getJSONObject(i);
        // Pulling items from the array
        String oneObjectsItem = oneObject.getString("STRINGNAMEinTHEarray");
        String oneObjectsItem2 = oneObject.getString("anotherSTRINGNAMEINtheARRAY");
    } catch (JSONException e) {
        // Oops
    }
}