如何使用纯WIN32 API调用为GUI应用程序创建调试控制台

问题描述：

我正在为WIN32 GUI应用程序创建一个调试控制台，我正试图以不同的方式做到这一点，而我的生活中我无法让这个工作，这是一个简单的事情，但它正在驱动我疯了。我知道这已被问过一百万次，一般的方式和我一直在使用的是：

I'm playing around with creating a debug console on for a WIN32 GUI app and I'm trying to do it a different way and by the life of me I cannot get this working, its such a simple thing but it's driving me crazy. I know this has been asked a million times before and the general way and what I have been using is this:

AllocConsole();

freopen("CON", "r", stdin);
freopen("CON", "w", stdout);
freopen("CON", "w", stderr);

或者

or also

OutputDebugString(TEXT("blah, blah blah");

我想太多的空闲时间/无聊/好奇心，或者有些奇怪的意愿以尽可能最难的方式做事，我想要尝试使用AllocConsole，CreateFile，SetStdHandle进行纯粹的WIN32调用。不管谷歌搜索多少或搜索MSDN，我都无法正常工作。所有功能都返回成功，控制台在屏幕上打开，但没有输入/ ouput。

我尝试过：

I guess too much free time/boredom/curiosity, or some strange will to do things the hardest way possible, I wanted to try doing it differently with just pure WIN32 calls with AllocConsole, CreateFile, SetStdHandle. No matter how much googling or searching through MSDN, I cant get this to work correctly. All the functions return successful and console opens up on the screen, but no input/ouput.

What I have tried:

AllocConsole();

HANDLE hConsoleSTDIN = CreateFile("CONIN$", GENERIC_READ | GENERIC_WRITE,
                                  FILE_SHARE_READ, 0, OPEN_EXISTING, 0, 0);

SetStdHandle(STD_INPUT_HANDLE, hConsoleSTDIN);

HANDLE hConsoleSTDOUT = CreateFile("CONOUT$", GENERIC_READ | GENERIC_WRITE,
                                   FILE_SHARE_WRITE, 0, OPEN_EXISTING, 0, 0);

SetStdHandle(STD_OUTPUT_HANDLE, hConsoleSTDOUT);

如果我是printf（）或std :: cout，则不会显示任何内容。

任何帮助都会很棒。

谢谢

Matt

if I printf() or std::cout, nothing is displayed.

Any help would be great.
Thanks
Matt

答

，GENERIC_READ | GENERIC_WRITE，
FILE_SHARE_READ，0，OPEN_EXISTING，0,0）;

SetStdHandle（STD_INPUT_HANDLE，hConsoleSTDIN）;

HANDLE hConsoleSTDOUT = CreateFile（CONOUT

", GENERIC_READ | GENERIC_WRITE, FILE_SHARE_READ, 0, OPEN_EXISTING, 0, 0); SetStdHandle(STD_INPUT_HANDLE, hConsoleSTDIN); HANDLE hConsoleSTDOUT = CreateFile("CONOUT

，GENERIC_READ | GENERIC_WRITE，
FILE_SHARE_WRITE，0，OPEN_EXISTING，0,0）;

SetStdHandle（STD_OUTPUT_HANDLE，hConsoleSTDOUT）;

", GENERIC_READ | GENERIC_WRITE, FILE_SHARE_WRITE, 0, OPEN_EXISTING, 0, 0); SetStdHandle(STD_OUTPUT_HANDLE, hConsoleSTDOUT);

如果我是printf（）或std :: cout，则不会显示任何内容。

任何帮助都会很棒。

谢谢

Matt

if I printf() or std::cout, nothing is displayed.

Any help would be great.
Thanks
Matt

我使用Console窗口来调试我的所有应用程序，无论是否有GUI。

I在大多数情况下使用纯Win32 API。

参见这篇文章 [ ^ ]

不仅可以，而且你可以设置颜色和字体样式。

首先，你打电话：

I use a Console window to debug all of my applications, with or without GUI.
I use pure Win32 API in most of the cases.
See This article[^]
Not only that it possible but you can set colors and font styles.
First, you call:

#include <conio.h>
HANDLE hConsole = GetStdHandle(STD_OUTPUT_HANDLE);

要设置文字颜色，我使用：

To set the text color, I use:

inline void setcolor(int textcol, int backcol)
{
	if ((textcol % 16) == (backcol % 16))textcol++;
	textcol %= 16; backcol %= 16;
	unsigned short wAttributes = ((unsigned)backcol << 4) | (unsigned)textcol;
	CONSOLE_SCREEN_BUFFER_INFO csbi;
	SetConsoleTextAttribute(hConsole, wAttributes);
}

然后，只需使用 wprintf（）即可显示文字。

如果您愿意要清除显示区域，只需致电：

Then, just use wprintf() to display the text.
If you wish to clear the display area, just call:

system("cls");

同时通过调用刷新显示：

Also refresh the display by calling:

void refresh()
{
	HWND hwnd = FindWindowEx(NULL, NULL, L"CabinetWClass", NULL);
	while (hwnd != NULL)
	{
		PostMessage(hwnd, WM_COMMAND, 41504, 0);
		hwnd = FindWindowEx(NULL, hwnd, L"CabinetWClass", NULL);
	}
}

如何使用纯WIN32 API调用为GUI应用程序创建调试控制台

相关推荐