如何在PHP中将字节数组转换为字符串?

如果按字节数组表示，则表示:

If by array of bytes you mean:

$bytes = array(255, 0, 55, 42, 17,    );

array_map()

那么就这么简单:

array_map()

Then it's as simple as:

$string = implode(array_map("chr", $bytes));

foreach()

哪个是以下版本的精简版本:

foreach()

Which is the compact version of:

$string = "";
foreach ($bytes as $chr) {
    $string .= chr($chr);
}
// Might be a bit speedier due to not constructing a temporary array.

pack()

但最可取的选择是使用pack("C*", [$array...])，即使它需要PHP中的时髦数组变通方法来传递整数列表:

pack()

But the most advisable alternative could be to use pack("C*", [$array...]), even though it requires a funky array workaround in PHP to pass the integer list:

$str = call_user_func_array("pack", array_merge(array("C*"), $bytes)));

如果您可能需要从字节 C * (对于ASCII字符串)切换到单词 S * (对于UCS2)，或者甚至具有一个 L * 的32位整数列表(例如UCS4 Unicode字符串).

That construct is also more useful if you might need to switch from bytes C* (for ASCII strings) to words S* (for UCS2) or even have a list of 32bit integers L* (e.g. a UCS4 Unicode string).