有没有更简洁的方法来初始化空的多维数组？

问题描述：

我一直试图找到一种相当简洁的方法来设置空的多维JavaScript数组的维度，但到目前为止还没有成功。

I've been trying to find a reasonably concise way to set the dimensions of an empty multidimensional JavaScript array, but with no success so far.

首先，我尝试使用 var theArray = new Array（10,10 10）初始化一个空的10x10x10数组，但相反，它只创建了一个包含3个元素的1维数组。

First, I tried to initialize an empty 10x10x10 array using var theArray = new Array(10, 10 10), but instead, it only created a 1-dimensional array with 3 elements.

我已经想出如何使用嵌套的for循环初始化一个空的10x10x10数组，但是用这种方式编写数组初始化器非常繁琐。使用嵌套for循环初始化多维数组可能非常繁琐：是否有更简洁的方法在JavaScript中设置空多维数组的维度（具有任意多个维度）？

I've figured out how to initialize an empty 10x10x10 array using nested for-loops, but it's extremely tedious to write the array initializer this way. Initializing multidimensional arrays using nested for-loops can be quite tedious: is there a more concise way to set the dimensions of empty multidimensional arrays in JavaScript (with arbitrarily many dimensions)?

//Initializing an empty 10x10x10 array:
var theArray = new Array();
for(var a = 0; a < 10; a++){
    theArray[a] = new Array();
    for(var b = 0; b < 10; b++){
        theArray[a][b] = new Array();
        for(var c = 0; c < 10; c++){
            theArray[a][b][c] = 10
        }
    }
}

console.log(JSON.stringify(theArray));

答

改编自这个答案：

function createArray(length) {
  var arr = new Array(length || 0),
      i = length;

  if (arguments.length > 1) {
    var args = Array.prototype.slice.call(arguments, 1);
    while(i--) arr[i] = createArray.apply(this, args);
  }        
  return arr;
 }

只需使用参数调用每个维度的长度即可。
用法示例：

Simply call with an argument for the length of each dimension. Usage examples:

var multiArray = createArray（10,10,10）; 给出一个等长的三维数组。

var weirdArray = createArray（34,6,42,2）; 给出一个不等长的4维数组。

var multiArray = createArray(10,10,10); Gives a 3-dimensional array of equal length.
var weirdArray = createArray(34,6,42,2); Gives a 4-dimensional array of unequal lengths.

有没有更简洁的方法来初始化空的多维数组？

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