将Q_GADGET作为信号参数从C ++传递到QML
无法在QML代码中获取C ++对象的属性. 对象作为参数传递给信号.
Can't get a property of a C++ object inside a QML code. Object is passed as a parameter to the signal.
预期在QML中,可以提取Record
对象的属性text
.并且该值应为abc
. QML将对象视为QVariant(Record)
,并将其属性text
视为undefined
.
Expected that in QML, the property text
of the Record
object can be extracted. And the value should be abc
. QML sees the object as QVariant(Record)
, and its property text
as undefined
.
Record
是类似于QPoint
的值类型,因此它使用Q_GADGET
声明.
Record
is a value-type like QPoint
, so it uses Q_GADGET
declaration.
hpp:
#ifndef LISTENP_HPP_
#define LISTENP_HPP_
#include <QObject>
#include "Record.hpp"
class ListenP: public QObject
{
Q_OBJECT
public:
ListenP();
virtual ~ListenP();
void emitGotRecord();
signals:
void gotRecord(Record r);
};
#endif /* LISTENP_HPP_ */
cpp:
#include "ListenP.hpp"
ListenP::ListenP() :
QObject()
{
}
ListenP::~ListenP()
{
}
void ListenP::emitGotRecord()
{
emit gotRecord(Record("abc"));
}
记录的hpp:
#ifndef RECORD_HPP_
#define RECORD_HPP_
#include <QObject>
#include <QMetaType>
class Record
{
Q_GADGET
Q_PROPERTY(QString text READ text WRITE setText)
public:
Record(const QString& text = "");
~Record();
QString text() const
{
return m_text;
}
void setText(const QString& text)
{
m_text = text;
}
private:
QString m_text;
};
Q_DECLARE_METATYPE(Record)
#endif /* RECORD_HPP_ */
记录的cpp:
#include "Record.hpp"
Record::Record(const QString& text) :
m_text(text)
{
}
Record::~Record()
{
}
namespace
{
const int RecordMetaTypeId = qMetaTypeId<Record>();
}
QML片段:
Connections {
target: listenPModel
onGotRecord: {
console.log(r)
console.log(r.text)
}
}
主要作品:
QGuiApplication app(argc, argv);
auto listenP = std::make_shared<ListenP>();
QQuickView view;
view.rootContext()->setContextProperty("listenPModel", &*listenP);
view.setSource(QStringLiteral("src/qml/main.qml"));
view.show();
QtConcurrent::run([=]
{
QThread::sleep(3);
listenP->emitGotRecord();
});
return app.exec();
日志显示:
qml: QVariant(Record)
qml: undefined
发行说明 Qt 5.5表示新功能:
The release notes for Qt 5.5 says for the new features:
- Qt核心
- 您可以现在在Q_GADGET中包含Q_PROPERTY和Q_INVOKABLE ,并且有一种方法可以使用QMetaType系统查询此类小工具的QMetaObject
- Qt Core
- You can now have Q_PROPERTY and Q_INVOKABLE within a Q_GADGET, and there is a way to query the QMetaObject of such gadget using the QMetaType system
实际上,使用Qt 5.4编译并运行您的示例所得到的结果与您使用Record
,即我得到了一个结果:
Indeed, compiling and running your example with Qt 5.4 gives the same result as yours whereas with Qt 5.5 I got Record
correctly recognised, i.e. I got as a result:
qml: Record(abc)
qml: abc
此外,如Q_DECLARE_METATYPE
文档所述,类型传递给宏-在这种情况下,Record
应该提供(1)公共默认构造函数,(2)公共副本构造函数和(3)公共析构函数.由于Record
是一个非常简单的类,因此无需提供副本构造函数,因为默认构造函数就足够了.
Also, as stated in the Q_DECLARE_METATYPE
documentation, the type passed to the macro - Record
in this case, should provide (1) a public default constructor, (2) a public copy constructor and (3) a public destructor. Since Record
is a very simple class, there's no need to provide a copy constructor as the default one is sufficient.