jQuery选择具有相同类的随机元素

问题描述：

我有类selectElement的元素。当我点击该类的元素，我选择它，并给它另一个类selectedElements，如果它还没有它。

I have elements with class "selectElement". When I click on element with that class, I "select" it, and give it another class "selectedElements", if it doesn't already have it.

我有一个按钮，应该随机选择一定数量（例如10）的元素与类selectElement，并给他们selectedElement类。

But, I have a button that should randomly select certain number (e.g. 10) of elements with class "selectElement" and give them the "selectedElement" class.

此答案 - > http://stackoverflow.com/a/1764629/1011539 ，但每次都返回相同的值。 ..

I tried something like in this answer -> http://stackoverflow.com/a/1764629/1011539, but it returns same values every time...

编辑：解决Jon的帮助。这是其他用户有类似问题的代码：）

Solved with Jon's help. Here is the code for other users with similar problem :)

$("#chooseElementsRand").live("click",function(){
    $(".selectedElements").removeClass("selectedElements");
    var maxNum = parseInt($(".maxNum").html());
    var randomElements = shuffle($(".selectElement")).slice(0,maxNum).addClass("selectedElements");
    $(".selectedNum").html(randomElements.length);
    if(randomElements.length==maxNum) {
        $(".buttonToProceed").removeClass("notShown");
    }
});

答

随机出现在X中，解决方案是 Fisher-Yates shuffle 。此网页具有Javascript实现（加上理由，加上漂亮的动画，因此请查看）：

Whenever you want to pick N elements really at random out of X, the solution is the Fisher-Yates shuffle. This page has a Javascript implementation (plus rationale, plus nice animations, so go have a look):

function shuffle(array) {
  var m = array.length, t, i;

  // While there remain elements to shuffle…
  while (m) {

    // Pick a remaining element…
    i = Math.floor(Math.random() * m--);

    // And swap it with the current element.
    t = array[m];
    array[m] = array[i];
    array[i] = t;
  }

  return array;
}

给定shuffle，然后可以随机选择X个元素

Given the shuffle, you can then pick X elements at random with

var items = shuffle($(".selectElement")).slice(0, X);

这里一个工作的小提琴 来玩。

Here's a working fiddle to play with.

脚注：由于你只对一定数量的随机选择感兴趣，所以没有必要无条件将整个输入数组作为 shuffle ;你可以只洗一小部分，然后使用 .slice 来剪掉它并使用它。我把这作为一个练习;注意，你不能错误地抓住* un * shuffle部分！

Footnote: since you are only interested in a certain amount of random picks, there's no need to unconditionally shuffle the whole input array as shuffle does above; you could shuffle only a small part and then use .slice to cut it off and work with it. I 'm leaving this as an exercise; be careful that you don't grab the *un*shuffled part by mistake!

jQuery选择具有相同类的随机元素

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