如何返回列表切片的最大元素

问题描述：

我正在尽最大努力简化此功能，怎么办?

I am trying to simplify this function at his maximum, how can I do?

def eleMax(items, start=0, end=None):
    if end is None:
        end = len(items)
    return max(items[start:end])

我想到了

def eleMax(items, start=0, end=-1):
    return max(items[start:end])

但是最后一个元素将从列表中删除.

But the last element is deleted from the list.

答

您可以删除以下两行:

if end is None:
    end = len(items)

该功能将完全相同:

>>> a=[5,4,3,2,1]
>>> def eleMax(items, start=0, end=None):
...     return max(items[start:end])
...
>>> eleMax(a,2)   # a[2:] == [3,2,1]
3