在Matlab中将向量作为索引的完整矩阵

问题描述：

让我们说我们有一个矩阵A1和两个向量v1和v2，如下所示:

Let us say that we have a matrix A1 and two vectors v1 and v2 as follow:

A1=zeros(5, 5);
v1=[1 2 3];
v2=[5 5 4];

是否有一种方法可以将v1和v2用作索引逐一替换A1的元素?即在A1(1，5)，A1(2，5)和A1(3，4)中插入一些元素.

Is there a way to replace the elements of A1 using v1 and v2 as indices one by one? i.e., insert in A1(1, 5), A1(2, 5), and in A1(3, 4) some elements.

以下内容完成v1和v2的所有组合.我只想要一张一张.即v1(1)与v2(1)，v1(2)与v2(2)，依此类推.

The following do all combinations of v1 and v2. I want only one by one. i.e., v1(1) with v2(1), v1(2) with v2(2), and so on.

A1(v1, v2)

答

基本上，您具有行和列信息，需要将它们转换为线性索引，才能索引为A1.为此，请使用 sub2ind -

Basically you have row and column information and need to convert them into a linear index, to index into A1. For this, use sub2ind -

A1(sub2ind(size(A1),v1(1),v2(1))) = 12
A1(sub2ind(size(A1),v1(2),v2(2))) = 10
A1(sub2ind(size(A1),v1(3),v2(3))) = 9

输出-

A1 =

     0     0     0     0    12
     0     0     0     0    10
     0     0     0     9     0
     0     0     0     0     0
     0     0     0     0     0

如果这些值存储在某个数组array1中，请使用与上面相同的结果-

If you have those values stored in some array, array1, use this for the same result as above -

array1 = [12 10 9];
A1(sub2ind(size(A1),v1,v2)) = array1;

在Matlab中将向量作为索引的完整矩阵

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