WCF:如何在没有WSDL:import的情况下生成单个WSDL文档?

问题描述：

我正在困扰一个问题... 我正在尝试寻找一种方法从WCF服务生成单个wsdl文档，即没有任何指向外部文档的链接. 我已经使用过 FlatWsdl 删除所有xsd:import链接，但是我生成的wsdl仍然包含通过wsdl:import声明指向外部wsdl文档的链接:

I'm troubling into an issue... I'm trying to find a way to generate a single wsdl document from my WCF service, i.e. without any link to external documents. I've used FlatWsdl to remove all xsd:import links, bou my generated wsdl still contains a link to an external wsdl document via a wsdl:import declaration:

<wsdl:import namespace="http://myurl/mynamespace"  
             location="http://myserver/myservice.svc?wsdl=wsdl0"/>

该文档实际上包含所有内联的xsd模式，所以...为了使一个wsdl单一，也可以内联此外部wsdl文档吗?

This document actually contains all inlined xsd schemas, so... there's a way to inline also this external wsdl document, in order to have a single wsdl?

非常感谢您提供任何帮助.

Thanks a lot for any kind of help.

答

(有关FlatWSDL的先前答案已删除，因为正如您所指出的，这是关于消除xsd:import而不是wsdl:import.)

( Previous answer about FlatWSDL deleted, because as you pointed out it was about eliminating xsd:import not wsdl:import.)

请参阅此博客文章:控制生成的WSDL在WCF中

"......总是为一个目标名称空间URI生成一个WSDL ..."

"... There is always one WSDL generated for one target namespace URI ..."

您是否为ServiceContract，DataContract，ServiceBehavior等使用不同的命名空间?

Do you have different namespace for ServiceContract, DataContract, ServiceBehavior, etc. ?

WCF:如何在没有WSDL:import的情况下生成单个WSDL文档?

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