在C中,最好的方法是查看一个数字是否可以被另一个整数整除?

在C中,最好的方法是查看一个数字是否可以被另一个整数整除?

问题描述:

在C语言中,哪一种是最好的方法来查看一个数字是否可以被另一个整数整除?我用这个:

Which is the best way, in C, to see if a number is divisible by another? I use this:

if (!(a % x)) {
// this will be executed if a is divisible by x
}

反正还有更快吗?我知道这样做,即130%13将导致每10次做130/13.因此,有10个周期只需要一个周期(我只想知道130是否可被13整除).

Is there anyway which is faster? I know that doing, i.e, 130 % 13 will result into doing 130 / 13 per 10 times. So there are 10 cycles when just one is needed (I just want to know if 130 is divisible by 13).

谢谢!

我知道,做130%13将导致每10次做130/13

I know that doing, i.e, 130 % 13 will result into doing 130 / 13 per 10 times

Balderdash. %在我使用过的任何处理器上均不执行此操作.它只执行一次130/13,然后返回其余的值.

Balderdash. % does no such thing on any processor I've ever used. It does 130/13 once, and returns the remainder.

使用%.如果您的应用程序运行太慢,请对其进行概要分析并修复所有太慢的问题.

Use %. If your application runs too slowly, profile it and fix whatever is too slow.