如何获得返回值与内部Ajax调用的函数 - JQuery的

问题描述：

这听起来可能很容易就你们几个，但我无法弄清楚，为什么我不能够得到的返回值，甚至chceking很多帖子后：（

this may sound very easy to few of you, but i am not able to figure out why I am not able to get the return value, even after chceking many posts :(

function getMessageCount() {
                    var count;
                    $.ajax({
                        type: "POST",
                        url: "http://localhost:43390" + "/services/DiscussionWidgetService.asmx/GetMessageCount",
                        dataType: "json",
                        contentType: "application/json; charset=utf-8",
                        success: function (data) {                            
                            count = data.d;
                        } //success
                    });
                    return count;
                }

现在如果我叫 VAR数= getMessageCount（）; 它给了我undefinted :( 而里面的方法计数到来正确的，即服务工作正常。

Now if I call var count = getMessageCount(); it gives me undefinted :( while inside the method count is coming correct, i.e. service is working fine.

答

这是因为 $。阿贾克斯（）调用是异步的。

That's because the $.ajax() call is asynchronous.

如果您修改了code到是这样的：

If you edit your code to something like:

function getMessageCount(callback) {
    var count;
    $.ajax({
       type: "POST",
       url: "http://localhost:43390" + "/services/DiscussionWidgetService.asmx/GetMessageCount",
       dataType: "json",
       contentType: "application/json; charset=utf-8",
       success: function (data) {                            
         count = data.d;

         if(typeof callback === "function") callback(count);
      } //success
   });
}

然后当你调用它：

Then when you call it:

getMessageCount(function(count){
  console.log(count);
});

如何获得返回值与内部Ajax调用的函数 - JQuery的

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