在 SpringBoot 客户端中使用 WebServiceTemplate 调用 SOAP Web 服务

问题描述：

我正在使用 WebServiceTemplate 调用 SOAP Web 服务.我可以通过以下输入使用 SOAP UI 调用服务并获得正确响应.

I am calling a SOAP web service using WebServiceTemplate. I am able to call the service using SOAP UI with following input and getting the correct response.

<soapenv:Envelope xmlns:soapenv="http://schemas.xmlsoap.org/soap/envelope/" xmlns:abc="http://abc.hs.com/">
      <soapenv:Header>
                <version>1<version>
   </soapenv:Header>
   <soapenv:Body>
      <abc:getUser>
         <userId>pan</userId>
      </abc:getUser>
   </soapenv:Body>
</soapenv:Envelope>

但是当使用 WebserviceTemplate 调用时，如下所示:

But when calling using WebserviceTemplate as below:

public String getUser(String userId) {
        List<String> detail = new ArrayList<String>();
        try {
            template = new WebServiceTemplate(marshaller);
            String requestPayload = getXmlInput();// This is same xml I am sending using SOAPUI 
            StreamSource source = new StreamSource(new StringReader(requestPayload));
            StreamResult result = new StreamResult(System.out);
            template.sendSourceAndReceiveToResult("http://localhost:8080/HERSvc/InsService", source,
                    new WebServiceMessageCallback() {
                        public void doWithMessage(WebServiceMessage message) throws IOException {
                        TransportContext context = TransportContextHolder.getTransportContext();
                        HttpUrlConnection connection = (HttpUrlConnection) context.getConnection();
                        connection.addRequestHeader("Content-Type", "text/xml; charset=utf-8");
                        connection.addRequestHeader("soapAction", "");
                }
            },result);
        } catch (IOException e) {
            e.printStackTrace();
        }
        return "";
    }

我在服务器端收到以下错误:E org.apache.axis2.engine.AxisEngine receive The endpoint reference (EPR) for the Operation not found is http://localhost:8080/HERSvc/InsService andWSA 行动 = .如果之前可以访问此 EPR，请联系服务器管理员.

I am getting following error at server side: E org.apache.axis2.engine.AxisEngine receive The endpoint reference (EPR) for the Operation not found is http://localhost:8080/HERSvc/InsService and the WSA Action = . If this EPR was previously reachable, please contact the server administrator.

客户端错误消息:出现意外错误(类型=内部服务器错误，状态=500).

Client side error message : There was an unexpected error (type=Internal Server Error, status=500).

经过 https://*.com/questions/5981379/the-endpoint-reference-epr-for-the-operation-not-found-is 我添加了 Content-Type 和标题中的soapAction

After going through https://*.com/questions/5981379/the-endpoint-reference-epr-for-the-operation-not-found-is I added Content-Type and soapAction in header

注意:我怀疑问题在于我的 requestPayload 格式不正确.它与 SOAP UI 中使用的字符串相同.似乎输入被转换为 Body

NOTE: I suspect problem is with my requestPayload which is not formed properly. It is same string used in SOAP UI. It seems the input is transformed as Body

<SOAP-ENV:Envelope xmlns:SOAP-ENV="http://schemas.xmlsoap.org/soap/envelope/">
<SOAP-ENV:Header/>
<SOAP-ENV:Body>
<soapenv:Envelope xmlns:abc="http://abc.hs.com/" xmlns:soapenv="http://schemas.xmlsoap.org/soap/envelope/">
    <soapenv:Header>
    <version>1<version>
</soapenv:Header>
    <soapenv:Body>
        <abc:getUser>
            <userId>pan</userId>
        </abc:getUser>
    </soapenv:Body>
</soapenv:Envelope>
</SOAP-ENV:Body>
</SOAP-ENV:Envelope>

答

问题是必需的 Header 格式不正确.最初我无法创建 objectPayload，因此无法使用 marshalSendAndReceive.因此，为了创建正确的 objectPayload，我使用 wsdl 从命令提示符生成 ObjectFactory，然后将创建的所有对象导入到项目中.使用 marshalSendAndReceive 如下

The issue was that required Header was not formed properly. Initially I wasn't able to create objectPayload, so unable to use marshalSendAndReceive. So, to create proper objectPayload I used my wsdl to generate ObjectFactory from command prompt and then imported all the objects created to the project. Use marshalSendAndReceive as follows

wsimport -d generated http://example.org/stock?wsdl

public User getUser(User user) {
        try {
            template = new WebServiceTemplate(marshaller);
            JAXBElement<?> response =  (JAXBElement<?>)template.marshalSendAndReceive("http://localhost:8080/HERSvc/InsService", 
            new ObjectFactory().createGetUser(user),
                    new WebServiceMessageCallback() {
                        public void doWithMessage(WebServiceMessage message) {
                            try {
                                SoapMessage soapMessage = (SoapMessage)message;
                                SoapHeader header = soapMessage.getSoapHeader();
                                StringSource headerSource = new StringSource("<version>1.0</version>");
                                        Transformer transformer = TransformerFactory.newInstance().newTransformer();
                                        transformer.transform(headerSource, header.getResult());
                            } catch (Exception e) {
                                e.printStackTrace();
                            }
                        }
                }) ;
        } catch (IOException e) {
            e.printStackTrace();
        }
        GetUserResponse responseObject = (GetUserResponse)response.getValue();
    User user = responseObject.getReturn();
    }

在 SpringBoot 客户端中使用 WebServiceTemplate 调用 SOAP Web 服务

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