如何通过使用C#.NET 4.5将文件从ZIP存档读取到内存，而无需先将其提取到文件中?

问题描述：

.NET Framework 4.5通过System.IO.Compression中的类添加了对ZIP文件的支持.

.NET Framework 4.5 added support for ZIP files via classes in System.IO.Compression.

比方说，我有.ZIP存档，其根目录中有sample.xml文件.我想直接从存档读取此文件到内存流，然后将其反序列化为自定义.NET对象.最好的方法是什么?

Let's say I have .ZIP archive that has sample.xml file in the root. I want to read this file directly from archive to memory stream and then deserialize it to a custom .NET object. What is the best way to do this?

答

从 XmlSerializer.Deserialize() 手册页.

Adapted from the ZipArchive and XmlSerializer.Deserialize() manual pages.

ZipArchiveEntry类具有Open()方法，该方法将流返回到文件.

The ZipArchiveEntry class has an Open() method, which returns a stream to the file.

string zipPath = @"c:\example\start.zip";

using (ZipArchive archive = ZipFile.OpenRead(zipPath))
{
    var sample = archive.GetEntry("sample.xml");
    if (sample != null)
    {
        using (var zipEntryStream = sample.Open())
        {               
            XmlSerializer serializer = new XmlSerializer(typeof(SampleClass));  

            SampleClass deserialized = 
                (SampleClass)serializer.Deserialize(zipEntryStream);
        }
    }
}

请注意，正如MSDN上记录的那样，您需要添加对.NET程序集System.IO.Compression.FileSystem的引用才能使用ZipFile类.

Note that, as documented on MSDN, you need to add a reference to the .NET assembly System.IO.Compression.FileSystem in order to use the ZipFile class.

如何通过使用C#.NET 4.5将文件从ZIP存档读取到内存，而无需先将其提取到文件中?

相关推荐