打印变量（或指针）的存储位置
问题描述：
我想打印一个变量的存储位置。我Google一下，我发现这一点：
I want to print where a variable is stored. I Google it and I found this:
int *p;
printf("memory location of ptr: %p\n", (void *)p);
如果我写这篇文章，是不是？
If I write this, is it right?
printf("memory location of ptr: %p\n", &p);
我编译它，我没有得到任何错误或警告，但载文，如果我把他们都在节目中的两个语句不返回相同的值。
I compiled it and I don't get any errors or warnings but theses two statements don’t return the same value if I put both of them in the program.
答
比方说你有这些声明：
int i;
int *p = &i;
这将是这个样子的记忆：
It would look something like this in memory:
+---+ +---+
| p | --> | i |
+---+ +---+
如果您再使用＆安培; P 你得到一个指针 P ，让你有这样的：
If you then use &p you get a pointer to p, so you have this:
+----+ +---+ +---+
| &p | --> | p | --> | i |
+----+ +---+ +---+
所以 P 的值为的地址我和的价值＆安培; p 是 p 的地址。这就是为什么你会得到不同的值。
So the value of p is the address of i, and the value of &p is the address of p. That's why you get different values.