如何在Python中将文本文件转换为列表

我在尝试将文本文件转换为以逗号分隔的列表列表时遇到麻烦.基本上，我想要:

I'm having trouble trying to convert a text file into a list of lists split by commas. Basically, I want:

DATE  OF OCCURRENCE,WARD,LONGITUDE,LATITUDE
06/04/2011,3,-87.61619704286184,41.82254380664193
06/04/2011,20,-87.62391924557963,41.79367531770095

外观如下:

[["DATE  OF OCCURRENCE", "WARD", "LONGITUDE" , "LATITUDE"],
 ["06/04/2011", "3", "-87.61619704286184", "41.82254380664193"],
 ["06/04/2011", "20", "-87.62391924557963", "41.79367531770095"]]

这是我到目前为止的代码:

Here is the code I have so far:

row = []
crimefile = open(fileName, 'r')
for line in crimefile.readlines():
    row.append([line])
    for i in line.split(","):
        row[-1].append(i)

但是，这使我得到了以下结果:

However, this gets me a result of:

[['DATE  OF OCCURRENCE,WARD,LONGITUDE,LATITUDE\n', 'DATE  OF OCCURRENCE', 'WARD', 'LONGITUDE', 'LATITUDE\n'], 
['06/04/2011,3,-87.61619704286184,41.82254380664193\n', '06/04/2011', '3', '-87.61619704286184', '41.82254380664193\n'], 
['06/04/2011,20,-87.62391924557963,41.79367531770095', '06/04/2011', '20', '-87.62391924557963', '41.79367531770095']]

我只希望能够删除第一部分并将其替换为第二部分.我该怎么办?

I just want to be able to remove that first part and replace it with the second. How can I do that?