android studio 3.1:build:gradle:3.1.0-设置输出文件名时不支持绝对路径

问题描述：

当我使用Android Studio 3.0 并且在project/build.gradle中使用下一版的 Android Gradle插件时:

When I use Android Studio 3.0 and I use the next version of Android Gradle Plugin in project/build.gradle:

classpath 'com.android.tools.build:gradle:3.0.1'

工作正常. 更新到Android Studio 3.1 后，结果更新了 Android Gradle插件:

And it's work fine. After I update to Android Studio 3.1 , as result I update Android Gradle Plugin :

classpath 'com.android.tools.build:gradle:3.1.0'

现在我的app/build.gradle出现错误:

def releaseFileName = "${rootProject.name}_${defaultConfig.versionName}.apk"
outputFileName = new File(rootProject.projectDir.absolutePath + "/release", releaseFileName.toLowerCase())

错误:

绝对路径

Absolute path are not supported when setting an output file name

我需要将输出apk(app-release.apk)放在项目中的特定路径中.在文件夹MyProject/release/app-relese.apk中.我该怎么做?

I need to put output apk (app-release.apk) in specific path in project. In folder MyProject/release/app-relese.apk. How I can do this?

答

我认为使用"./../../../"是不好的解决方案...我在多个项目中使用通用gradle脚本，我想使代码独立于输出目录的深度.

I think using "./../../../" is bad solution... I use common gradle script for several projects and I want to make code to be independency from depth of output dir.

经过一番研究，我找到了适用于gradle插件3.1.2的解决方案:

After some researching I found this solution for gradle plugin 3.1.2:

applicationVariants.all { variant ->
    variant.outputs.all { output ->
        def relativeRootDir = output.packageApplication.outputDirectory.toPath()
                 .relativize(rootDir.toPath()).toFile()
        output.outputFileName = new File( "$relativeRootDir/release", newOutputName)
    }
}

android studio 3.1:build:gradle:3.1.0-设置输出文件名时不支持绝对路径

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