致命错误:不支持的操作数类型

我一直收到以下错误，我想知道如何解决它.

I Keep getting the following error and I was wondering on how to fix it.

Fatal error: Unsupported operand types on line 97

它围绕下面列出的这段代码.如果需要，我可以列出完整的代码.

Its around this area of code listed below. I can list the full code if needed.

PHP代码

$total_rating_points = mysqli_fetch_array($result);
if (!empty($total_rating_points) && !empty($total_ratings)){
    $avg = (round($total_rating_points / $total_ratings,1));
    $votes = $total_ratings;
    echo $avg . "/10  (" . $votes . " votes cast)";
} else {
    echo '(no votes cast)';
}

这是第97行

$avg = (round($total_rating_points / $total_ratings,1));

这是完整的代码.

function getRatingText(){
    $dbc = mysqli_connect ("localhost", "root", "", "sitename");

    $page = '3';

    $sql1 = "SELECT COUNT(*) 
             FROM articles_grades 
             WHERE users_articles_id = '$page'";

    $result = mysqli_query($dbc,$sql1);

    if (!mysqli_query($dbc, $sql1)) {
            print mysqli_error($dbc);
            return;
    }

    $total_ratings = mysqli_fetch_array($result);

    $sql2 = "SELECT COUNT(*) 
             FROM grades 
             JOIN articles_grades ON grades.id = articles_grades.grade_id
             WHERE articles_grades.users_articles_id = '$page'";

    $result = mysqli_query($dbc,$sql2);

    if (!mysqli_query($dbc, $sql2)) {
            print mysqli_error($dbc);
            return;
    }

    $total_rating_points = mysqli_fetch_array($result);
    if (!empty($total_rating_points) && !empty($total_ratings)){
        $avg = (round($total_rating_points / $total_ratings,1));
        $votes = $total_ratings;
        echo $avg . "/10  (" . $votes . " votes cast)";
    } else {
        echo '(no votes cast)';
    }
}