当你在我的richtextbox中输入文本时,如果按下回车键,它会自动点击发送信息的按钮,我怎么能这样做呢?

当你在我的richtextbox中输入文本时,如果按下回车键,它会自动点击发送信息的按钮,我怎么能这样做呢?

问题描述:

我已经在最后一部分尝试了解一些事情,我想我只是在按下输入时切换到发送按钮,但是如何让它点击按钮?

Button2顺便说一句就是发送按钮...



I've tried in last part to figure something out and I think I just have got it to switch to the send button when hitting enter but how do i make it click the button?
Button2 is the send button by the way...

using System;
using System.Collections.Generic;
using System.ComponentModel;
using System.Data;
using System.Drawing;
using System.Linq;
using System.Text;
using System.Windows.Forms;
using System.Net;
using System.Net.Sockets;


namespace Chat_Program
{
    public partial class Form1 : Form
    {
        Socket sck;
        EndPoint epLocal, epRemote;
        byte[] buffer;

        public Form1()
        {
            InitializeComponent();
        }

        private void Form1_Load(object sender, EventArgs e)
        {
            {
                //set up socket
                sck = new Socket(AddressFamily.InterNetwork, SocketType.Dgram, ProtocolType.Udp);
                sck.SetSocketOption(SocketOptionLevel.Socket, SocketOptionName.ReuseAddress, true);

                // get user IP
                textBox1.Text = GetLocalIP();
                textBox3.Text = GetLocalIP();

                {

                }

            }
        }

        private string GetLocalIP()
        {
            IPHostEntry host;
            host = Dns.GetHostEntry(Dns.GetHostName());
            foreach (IPAddress ip in host.AddressList)
            {
                if (ip.AddressFamily == AddressFamily.InterNetwork)
                    return ip.ToString();

            }

            return "192.168.0.1";
        }

        private void button1_Click(object sender, EventArgs e)
        {
            //binding Socket
            epLocal = new IPEndPoint(IPAddress.Parse(textBox1.Text), Convert.ToInt32(textBox2.Text));
            sck.Bind(epLocal);
            //Connecting to remote IP
            epRemote = new IPEndPoint(IPAddress.Parse(textBox3.Text), Convert.ToInt32(textBox4.Text));
            sck.Connect(epRemote);
            //Listening the specific port
            buffer = new byte[1500];
            sck.BeginReceiveFrom(buffer, 0, buffer.Length, SocketFlags.None, ref epRemote, new AsyncCallback(MessageCallBack), buffer);
            button1.Enabled = false;
            richTextBox1.Enabled = true;
            label5.Text = "Connected...";

        }

        private void MessageCallBack(IAsyncResult aResult)
        {
            try
            {

                byte[] receivedData = new byte[1500];
                receivedData = (byte[])aResult.AsyncState;
                //Converting byte[] to string
                ASCIIEncoding aEncoding = new ASCIIEncoding();
                string receivedMessage = aEncoding.GetString(receivedData);

                //Adding this message into Listbox
                listBox1.ForeColor = System.Drawing.Color.Red;
                listBox1.Items.Add("Friend: " + receivedMessage);

                buffer = new byte[1500];
                sck.BeginReceiveFrom(buffer, 0, buffer.Length, SocketFlags.None, ref epRemote, new AsyncCallback(MessageCallBack), buffer);


            }

            catch (Exception ex)
            {
                MessageBox.Show(ex.ToString());

            }


        }

        private void button2_Click(object sender, EventArgs e)
        {
            //Convert string message to byte[]
            ASCIIEncoding aEncoding = new ASCIIEncoding();
            byte[] sendingMessage = new byte[1500];
            sendingMessage = aEncoding.GetBytes(richTextBox1.Text);
            //Sending the Encoded message
            sck.Send(sendingMessage);
            //adding to the listbox
            listBox1.Items.Add("Me: " + richTextBox1.Text);
            richTextBox1.Text = "";


        }


        private void button3_Click(object sender, EventArgs e)
        {

        }

        private void richTextBox1_TextChanged(object sender, EventArgs e)
        {

            if (string.IsNullOrEmpty(richTextBox1.Text))
            {
                button2.Enabled = false;

            }
            else
            {
                button2.Enabled = true;

            }
        }

        private void button3_Click_1(object sender, EventArgs e)
        {


            label5.Text = "Disconnected!";
            sck.Disconnect(true);


        }

        private void button4_Click(object sender, EventArgs e)
        {
            Form1 form1 = new Form1();
            Form2 form2 = new Form2();
            Form3 form3 = new Form3();

            Application.Exit();


        }

        private void button5_Click(object sender, EventArgs e)
        {
            this.WindowState = FormWindowState.Minimized;
        }

        private void label5_TextChanged(object sender, EventArgs e)
        {

            {

            }
        }

        private void Form1_FormClosing(object sender, FormClosingEventArgs e)
        {
            Form1 form1 = new Form1();
            Form2 form2 = new Form2();
            Form3 form3 = new Form3();

            Application.Exit();

        }

        private void Form1_DoubleClick(object sender, EventArgs e)
        {
            SendKeys.Send("{ENTER}");
        }

        private void richTextBox1_KeyDown(object sender, KeyEventArgs e)
        {
            if (e.KeyCode == Keys.Enter)
            {
                // something
                button2.Focus();
                
            }

        }

    }
}

我想我假设这是ac#winforms应用程序?如果是,请选择表单。名为AcceptButton的表单上的属性设置为button2。这应该是输入键的默认值。
I guess I'm assuming this is a c# winforms application? If so, select the form. There is a property on the form called "AcceptButton" set that to your button2. That should make it the default for the "enter" key.