当你在我的richtextbox中输入文本时,如果按下回车键,它会自动点击发送信息的按钮,我怎么能这样做呢?
问题描述:
我已经在最后一部分尝试了解一些事情,我想我只是在按下输入时切换到发送按钮,但是如何让它点击按钮?
Button2顺便说一句就是发送按钮...
I've tried in last part to figure something out and I think I just have got it to switch to the send button when hitting enter but how do i make it click the button?
Button2 is the send button by the way...
using System;
using System.Collections.Generic;
using System.ComponentModel;
using System.Data;
using System.Drawing;
using System.Linq;
using System.Text;
using System.Windows.Forms;
using System.Net;
using System.Net.Sockets;
namespace Chat_Program
{
public partial class Form1 : Form
{
Socket sck;
EndPoint epLocal, epRemote;
byte[] buffer;
public Form1()
{
InitializeComponent();
}
private void Form1_Load(object sender, EventArgs e)
{
{
//set up socket
sck = new Socket(AddressFamily.InterNetwork, SocketType.Dgram, ProtocolType.Udp);
sck.SetSocketOption(SocketOptionLevel.Socket, SocketOptionName.ReuseAddress, true);
// get user IP
textBox1.Text = GetLocalIP();
textBox3.Text = GetLocalIP();
{
}
}
}
private string GetLocalIP()
{
IPHostEntry host;
host = Dns.GetHostEntry(Dns.GetHostName());
foreach (IPAddress ip in host.AddressList)
{
if (ip.AddressFamily == AddressFamily.InterNetwork)
return ip.ToString();
}
return "192.168.0.1";
}
private void button1_Click(object sender, EventArgs e)
{
//binding Socket
epLocal = new IPEndPoint(IPAddress.Parse(textBox1.Text), Convert.ToInt32(textBox2.Text));
sck.Bind(epLocal);
//Connecting to remote IP
epRemote = new IPEndPoint(IPAddress.Parse(textBox3.Text), Convert.ToInt32(textBox4.Text));
sck.Connect(epRemote);
//Listening the specific port
buffer = new byte[1500];
sck.BeginReceiveFrom(buffer, 0, buffer.Length, SocketFlags.None, ref epRemote, new AsyncCallback(MessageCallBack), buffer);
button1.Enabled = false;
richTextBox1.Enabled = true;
label5.Text = "Connected...";
}
private void MessageCallBack(IAsyncResult aResult)
{
try
{
byte[] receivedData = new byte[1500];
receivedData = (byte[])aResult.AsyncState;
//Converting byte[] to string
ASCIIEncoding aEncoding = new ASCIIEncoding();
string receivedMessage = aEncoding.GetString(receivedData);
//Adding this message into Listbox
listBox1.ForeColor = System.Drawing.Color.Red;
listBox1.Items.Add("Friend: " + receivedMessage);
buffer = new byte[1500];
sck.BeginReceiveFrom(buffer, 0, buffer.Length, SocketFlags.None, ref epRemote, new AsyncCallback(MessageCallBack), buffer);
}
catch (Exception ex)
{
MessageBox.Show(ex.ToString());
}
}
private void button2_Click(object sender, EventArgs e)
{
//Convert string message to byte[]
ASCIIEncoding aEncoding = new ASCIIEncoding();
byte[] sendingMessage = new byte[1500];
sendingMessage = aEncoding.GetBytes(richTextBox1.Text);
//Sending the Encoded message
sck.Send(sendingMessage);
//adding to the listbox
listBox1.Items.Add("Me: " + richTextBox1.Text);
richTextBox1.Text = "";
}
private void button3_Click(object sender, EventArgs e)
{
}
private void richTextBox1_TextChanged(object sender, EventArgs e)
{
if (string.IsNullOrEmpty(richTextBox1.Text))
{
button2.Enabled = false;
}
else
{
button2.Enabled = true;
}
}
private void button3_Click_1(object sender, EventArgs e)
{
label5.Text = "Disconnected!";
sck.Disconnect(true);
}
private void button4_Click(object sender, EventArgs e)
{
Form1 form1 = new Form1();
Form2 form2 = new Form2();
Form3 form3 = new Form3();
Application.Exit();
}
private void button5_Click(object sender, EventArgs e)
{
this.WindowState = FormWindowState.Minimized;
}
private void label5_TextChanged(object sender, EventArgs e)
{
{
}
}
private void Form1_FormClosing(object sender, FormClosingEventArgs e)
{
Form1 form1 = new Form1();
Form2 form2 = new Form2();
Form3 form3 = new Form3();
Application.Exit();
}
private void Form1_DoubleClick(object sender, EventArgs e)
{
SendKeys.Send("{ENTER}");
}
private void richTextBox1_KeyDown(object sender, KeyEventArgs e)
{
if (e.KeyCode == Keys.Enter)
{
// something
button2.Focus();
}
}
}
}
答
我想我假设这是ac#winforms应用程序?如果是,请选择表单。名为AcceptButton的表单上的属性设置为button2。这应该是输入键的默认值。
I guess I'm assuming this is a c# winforms application? If so, select the form. There is a property on the form called "AcceptButton" set that to your button2. That should make it the default for the "enter" key.