对采用类< T>的方法进行存根作为参数与Mockito

问题描述：

有一个通用的方法，接受一个类作为参数，我有问题，它与Mockito stubbing。方法如下：

There is a generic method that takes a class as parameter and I have problems stubbing it with Mockito. The method looks like this:

public <U extends Enum<U> & Error, T extends ServiceResponse<U>> T validate(
    Object target, Validator validator, Class<T> responseClass,
    Class<U> errorEnum);

这是上帝可怕，至少对我...我可以想象生活没有它，的代码库很高兴地使用它...

It's god awful, at least to me... I could imagine living without it, but the rest of the code base happily uses it...

我将在我的单元测试中，stub这个方法返回一个新的空对象。但是我怎么做这个与mockito？我试过：

I was going to, in my unit test, stub this method to return a new empty object. But how do I do this with mockito? I tried:

when(serviceValidatorStub.validate(
    any(), 
    isA(UserCommentRequestValidator.class), 
    UserCommentResponse.class, 
    UserCommentError.class)
).thenReturn(new UserCommentResponse());

但是由于我混合和匹配匹配器和原始值，我得到org.mockito.exceptions。

but since I am mixing and matching matchers and raw values, I get "org.mockito.exceptions.misusing.InvalidUseOfMatchersException: Invalid use of argument matchers!"

答

问题是，你不能混合参数匹配器和真正的参数在嘲笑的电话。所以，而是这样做：

The problem is, you cannot mix argument matchers and real arguments in a mocked call. So, rather do this:

when(serviceValidatorStub.validate(
    any(),
    isA(UserCommentRequestValidator.class),
    eq(UserCommentResponse.class),
    eq(UserCommentError.class))
).thenReturn(new UserCommentResponse());

注意使用 eq（）

请参阅： http://docs.mockito.googlecode.com/hg/org/mockito/Mockito.html#3

此外，您可以使用 参数匹配器类<？> types - 这匹配相同的标识，如 == Java运算符。

Also, you could use the same() argument matcher for Class<?> types - this matches same identity, like the == Java operator.

对采用类< T>的方法进行存根作为参数与Mockito

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