等待Promise.all()和多个等待之间的任何区别?
之间有什么区别:
const [result1, result2] = await Promise.all([task1(), task2()]);
和
const t1 = task1();
const t2 = task2();
const result1 = await t1;
const result2 = await t2;
和
const [t1, t2] = [task1(), task2()];
const [result1, result2] = [await t1, await t2];
出于本回答的目的,我将使用一些示例方法:
For the purposes of this answer I will be using some example methods:
-
res(ms)
是一个取整数的函数毫秒并返回一个在很多毫秒后解析的promise。 -
rej(ms)
是一个需要整数毫秒的函数返回一个在很多毫秒后拒绝的承诺。
-
res(ms)
is a function that takes an integer of milliseconds and returns a promise that resolves after that many milliseconds. -
rej(ms)
is a function that takes an integer of milliseconds and returns a promise that rejects after that many milliseconds.
调用 res
启动计时器。在所有延迟完成后,使用 Promise.all
等待一些延迟将解决,但请记住它们同时执行:
Calling res
starts the timer. Using Promise.all
to wait for a handful of delays will resolve after all the delays have finished, but remember they execute at the same time:
const data = await Promise.all([res(3000), res(2000), res(1000)])
// ^^^^^^^^^ ^^^^^^^^^ ^^^^^^^^^
// delay 1 delay 2 delay 3
//
// ms ------1---------2---------3
// =============================O delay 1
// ===================O delay 2
// =========O delay 3
//
// =============================O Promise.all
async function example() {
const start = Date.now()
let i = 0
function res(n) {
const id = ++i
return new Promise((resolve, reject) => {
setTimeout(() => {
resolve()
console.log(`res #${id} called after ${n} milliseconds`, Date.now() - start)
}, n)
})
}
const data = await Promise.all([res(3000), res(2000), res(1000)])
console.log(`Promise.all finished`, Date.now() - start)
}
example()
这意味着 Promise.all
将在3秒后解决内部承诺中的数据。
This means that Promise.all
will resolve with the data from the inner promises after 3 seconds.
但是, Promise.all
有快速失败行为:
But, Promise.all
has a "fail fast" behavior:
const data = await Promise.all([res(3000), res(2000), rej(1000)])
// ^^^^^^^^^ ^^^^^^^^^ ^^^^^^^^^
// delay 1 delay 2 delay 3
//
// ms ------1---------2---------3
// =============================O delay 1
// ===================O delay 2
// =========X delay 3
//
// =========X Promise.all
async function example() {
const start = Date.now()
let i = 0
function res(n) {
const id = ++i
return new Promise((resolve, reject) => {
setTimeout(() => {
resolve()
console.log(`res #${id} called after ${n} milliseconds`, Date.now() - start)
}, n)
})
}
function rej(n) {
const id = ++i
return new Promise((resolve, reject) => {
setTimeout(() => {
reject()
console.log(`rej #${id} called after ${n} milliseconds`, Date.now() - start)
}, n)
})
}
try {
const data = await Promise.all([res(3000), res(2000), rej(1000)])
} catch (error) {
console.log(`Promise.all finished`, Date.now() - start)
}
}
example()
如果您使用 async-await
,则必须等待每个承诺按顺序解析,这可能不是高效:
If you use async-await
instead, you will have to wait for each promise to resolve sequentially, which may not be as efficient:
const delay1 = res(3000)
const delay2 = res(2000)
const delay3 = rej(1000)
const data1 = await delay1
const data2 = await delay2
const data3 = await delay3
// ms ------1---------2---------3
// =============================O delay 1
// ===================O delay 2
// =========X delay 3
//
// =============================X await
async function example() {
const start = Date.now()
let i = 0
function res(n) {
const id = ++i
return new Promise((resolve, reject) => {
setTimeout(() => {
resolve()
console.log(`res #${id} called after ${n} milliseconds`, Date.now() - start)
}, n)
})
}
function rej(n) {
const id = ++i
return new Promise((resolve, reject) => {
setTimeout(() => {
reject()
console.log(`rej #${id} called after ${n} milliseconds`, Date.now() - start)
}, n)
})
}
try {
const delay1 = res(3000)
const delay2 = res(2000)
const delay3 = rej(1000)
const data1 = await delay1
const data2 = await delay2
const data3 = await delay3
} catch (error) {
console.log(`await finished`, Date.now() - start)
}
}
example()