如何在Oracle SQL中将行转换为列

问题描述：

对于一项要求，我必须创建一个查询以显示每周的员工时间表.查询是这样的:

For a requirement I have to create a query to show Employees Schedule per week. Query is like this:

select weekday, sched_hrs
  from table
 where emplid = '12345'
   and weekday_name= 1

此查询的输出如下:

Weekday |  Sched_hrs
-------------------- 
   1    |    7.6
   1    |    7.6
   1    |    7.6
   1    |    7.6
   1    |    7.6
   1    |    OFF
   1    |    OFF

我想要以下格式的输出:

I want the output in below format:

1   7.6  7.6   7.6   7.6   7.6   OFF  OFF

如何实现?

答

如果您对串联列表没问题，请使用中引入的 LISTAGG .

If you are OK with concatenated list, then use LISTAGG which was introduced in Oracle 11g Release 2.

SELECT weekday, LISTAGG(Sched_hrs, ',') WITHIN GROUP (ORDER BY weekday) AS Sched_hrs
FROM   table 
 WHERE emplid = '12345' AND weekday_name= 1
GROUP BY weekday;

例如

SQL> column employees format a50
SQL> SELECT deptno, LISTAGG(ename, ',') WITHIN GROUP (ORDER BY ename) AS employees
  2  FROM   emp
  3  GROUP BY deptno;

    DEPTNO EMPLOYEES
---------- --------------------------------------------------
        10 CLARK,KING,MILLER
        20 ADAMS,FORD,JONES,SCOTT,SMITH
        30 ALLEN,BLAKE,JAMES,MARTIN,TURNER,WARD

SQL>

如何在Oracle SQL中将行转换为列

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