sinon.js存根 - 你可以在单个存根函数上调用多个回调吗？

问题描述：

如果我有一个带有2个回调的函数的存根，当调用存根函数时，如何将sinon.js连接到调用两个回调？

If I have a stub for a function that takes 2 callbacks, how can I wire up sinon.js to call both callbacks when the stubbed function is invoked?

例如 - 这里是我想要存根的函数，它将2个函数作为参数：

For example - here's function that I want to stub which takes 2 functions as arguments:

function stubThisThing(one, two) {
   ... one and two are functions ...
   ... contents stubbed by sinon.js ...
}

我可以使用sinon来调用其中一个参数：

I can use sinon to call either one of the arguments:

stubbedThing.callsArg(0);

或

stubbedThing.callsArg(1);

但我似乎无法将两者都称为。如果我尝试：

stubbedThing.callsArg(0).callsArg(1);

或

stubbedThing.callsArg(0);
stubbedThing.callsArg(1);

然后sinon只会调用第二个参数。如果我按照其他顺序连接它，那么sinon将调用第一个arg。但是，我希望两者都被一个接一个地调用。

then sinon will only ever call the second argument. If I wire it up in the other order, then sinon will call the first arg. However, I'd like both to be called one after the other.

答

这不是一个经典的场景，因为不是很多方法会顺序调用两个方法，我猜这就是为什么它不受支持。但是，要保持冷静，解决方案很简单：

This is not a classic scenario, since not many methods would call two methods sequentially, and I guess thats why it isn't supported. But, be calm, the solution is easy:

var subject = { 
    method: function(one, two) {} 
};

var stub = sinon.stub(subject, 'method', function(one, two) { 
    one(); 
    two(); 
});

subject.method(
    function() { console.log('callback 1'); }, 
    function() { console.log('callback 2'); });

旁注：这也提供了选择是否应首先调用一个或两个的选项。

sinon.js存根 - 你可以在单个存根函数上调用多个回调吗？

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