如何在C＃中将字符串值列表从一个表单传递到另一个表单？

请参阅此链接 http://*.com/questions/12768674/send-data-from-one-page-to-another-in-c-sharp -asp-net [ ^ ]

参考这些链接。



在Windows窗体之间传递数据 [ ^ ]



http://*.com/questions/7886544/从一种形式传递到另一种形式的价值 [ ^ ]

Refer these links.

Passing Data between Windows Forms[^]

http://*.com/questions/7886544/passing-a-value-from-one-form-to-another-form[^]

根据您的场景，我创建了一个示例，让您了解我们如何将字符串集合从一个表单传递到另一个表单： -



让我说有两种形式如下： -

ContainForm：保存需要发送的数据。

GetForm：从ContainForm获取数据的表格。



现在我们可以在GettingForm中拥有属性来设置stringcollection，然后再从第一个表单打开表单。



GettingForm.cs

--------------

As per your scenario i have created an example to get you understand how we can pass string collection from one form to another :-

Let say i have two forms as below :-
ContainForm : Holds data which needs to be send.
GettingForm : Form which gets data from ContainForm.

Now we can have property in GettingForm to set the stringcollection before opening the form from first form.

GettingForm.cs
--------------

public partial class GettingForm : Form
    {
        public StringCollection DummyList { get; set; }

        public GettingForm()
        {
            InitializeComponent();
        }

        private void GettingForm_Load(object sender, System.EventArgs e)
        {
            foreach (string str in this.DummyList)
            {
                MessageBox.Show(str);
            }
        }
    }

ContainForm.cs

- --------------

ContainForm.cs
---------------

public partial class ContainForm : Form
    {
        public StringCollection DummyList { get; set; }

        public ContainForm()
        {
            InitializeComponent();
        }

        private void ContainForm_Load(object sender, System.EventArgs e)
        {
            DummyList = new StringCollection();
            DummyList.Add("Item 1");
            DummyList.Add("Item 2");
            DummyList.Add("Item 3");
            DummyList.Add("Item 4");
        }

        private void button1_Click(object sender, System.EventArgs e)
        {
            GettingForm gtForm = new GettingForm(); // create instance of GettingForm
            gtForm.DummyList = this.DummyList; // Assign value to the string collection propery of GettingForm
            gtForm.Show(); // Display the form
        }
    }

希望这对你有所帮助。



那里您也可以获得更多替代方案此处 [ ^ ]。