{error =“ invalid_request”; “ error_description” =“缺少必需的参数：grant_type”；迅速

${error =“ invalid_request”; “ error_description” =“缺少必需的参数：grant_type”；迅速$

问题描述：

I am trying with this but every time I will get 

{     error = "invalid_request";     "error_description" = "Required parameter is missing: grant_type"; }

Request String: 

let headers    = [ "Content-Type" : "application/x-www-form-urlencoded"]

let urlString = "https://accounts.google.com/o/oauth2/token?"

Alamofire.request(urlString, method: .post, parameters: ["grant_type":"authorization_code","code":"4/FAOYR1mQo1lN1Gdg9jDnigwZ8RP76NUrqPbYZlMCSP28","client_id":"387376833747-12pbtud9tepr4di0insdhc0d4qpf5e9m.apps.googleusercontent.com","client_secret":"xOacVhLavM9fH8SpOK4I2dRJ","redirect_uri":"https://stackoverflow.com"], encoding: JSONEncoding.default, headers : headers)
            .responseJSON { response in
                print(response)
                print(response.result)
        }

也可以尝试传递这样的请求参数，但对我仍然不起作用。

Also try with passing request parameter like this but still doesn't work for me.

答

您不能使用以下命令发送附加参数发送请求时的网址。
传递参数，如下所示

You can't send appended parameter with url while post request. Pass parameter as below this

  let headers    = [ "Content-Type" : "application/x-www-form-urlencoded","grant_type" : "authorization_code"" ]

        let urlString = "https://accounts.google.com/o/oauth2/token?"
            Alamofire.request(urlString, method: .post, parameters: ["code":"4/FAOYR1mQo1lN1Gdg9jDnigwZ8RP76NUrqPbYZlMCSP28","client_id":"apps.googleusercontent.com","client_secret":"","redirect_uri":"https://stackoverflow.com"], encoding: JSONEncoding.default, headers : headers)
                .responseJSON { response in
                    print(response)
                    print(response.result)
            }

{error =“ invalid_request”; “ error_description” =“缺少必需的参数：grant_type”；迅速

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