唯一编号C#网
嘿那里.
如何在vc#中获得1到75之间的3个唯一数字?
它不是作业，只是需要使用哪种方法的一些帮助
//我有一个程序，该程序应生成3个随机唯一数字，并应将其打印在3个不同的标签上. (第一名，第二名，第三名)
我已经开发出一种解决方案，但某些东西(不是很常见)输出2个相等的数字
因此，是否有任何函数或方法每次在一个范围(例如)之间生成唯一的数字. (1，75)
ty all:)
hey there.
how can i get 3 unique numbers between 1 and 75 in vc#?
it is not homework just need some help on which method to use
// i have a program that should generate 3 random unique numbers that should be printed out on 3 different labels. (1st winner, 2nd winner, 3rd winner)
I already developed a solution but somethimes (not often) it ouputs 2 equal numbers
so is there any function or method that generates unique numbers everytime between a range eg. (1, 75)
ty all :)
您尝试过类似的东西吗?
Have you tried something like this?
System.Random RandNum = new System.Random();
Label1.Text = RandNum.Next(1, 75).ToString();
Label2.Text = RandNum.Next(1, 75).ToString();
Label3.Text = RandNum.Next(1, 75).ToString();
我已经开发了一种解决方案，但是某些(不是经常)它输出2个相等的数字
I already developed a solution but somethimes (not often) it ouputs 2 equal numbers
如果您要生成随机数，则有可能两次生成相同的数字.但是，如果您不希望仅将生成的随机数存储在数组中，并确保数组中的每个元素在添加之前都是唯一的，那么在这种情况下，如果数组中已经存在任何数字，则生成一个新数.一旦获得数组中的所有数字，就将这些值分配给所需的标签.
If you are generating random number there might be a chance that same number can be generated twice. But if you don''t want that just store the generated random number in a array and make sure that each element of the array is unique before adding to it, if any number is already present in the array in that case generate a new number. Once you got all the number in the array assign these values to the desired labels.